Sql Order by on multiple column

Question

I\'ve the below result

VendorName | IncidentID | IncidentStatus | IncidentDate
-------------------------------------------------------
XYZ        | 100        |         


        

Answer 1

Use analytic functions:

SELECT *
FROM(
    SELECT 
        VendorName, 
        IncidentID, 
        IncidentStatus, 
        IncidentDate, 
        MAX(IncidentDate) OVER (PARTITION BY VendorName) maxDate
    FROM yourTable
) t
ORDER BY t.maxDate DESC, t.VendorName ASC, t.IncidentDate DESC

Refer to: http://docs.oracle.com/javadb/10.8.2.2/ref/rrefsqlj13658.html http://docs.oracle.com/cd/E11882_01/server.112/e10592/functions003.htm http://docs.oracle.com/cd/E11882_01/server.112/e26088/functions004.htm

Answer 2

This will do it ...

ORDER BY MAX(INCIDENTDATE) OVER (PARTITION BY VENDORNAME) DESC, INCIDENTDATE DESC

... but I'm not sure if the analytic function is allowed in the ORDER BY. If it isn't, calculate it in a subquery and order by in the main query ...

select ...
from   (
  select Max(incidentdate) over (partition by vendorname) max_incidentdate_by_vendor,
         ...)
order by max_incidentdate_by_vender desc, incidentdate desc

Answer 3

If you are on a RAC installation

set linesize 300
column REDOLOG_FILE_NAME format a50
SELECT
    a.INST_ID,
    a.GROUP#,
    a.THREAD#,
    a.SEQUENCE#,
    a.ARCHIVED,
    a.STATUS,
    b.MEMBER    AS REDOLOG_FILE_NAME,
    (a.BYTES/1024/1024/1024) AS SIZE_GB
FROM gv$log a
JOIN gv$logfile b ON a.Group#=b.Group# 
AND a.INST_ID=b.INST_ID 
ORDER BY a.INST_ID ASC, a.GROUP# ASC;

Answer 4

select vendorname, incidentid, incidentstatus, incidentdate, max(incidentdate) 
over (partition by vendorname order by incidentdate desc) max_incidentdate
from t1 order by max_incidentdate desc, incidentdate desc