I am new to the mvvm pattern. I created a ViewModel for the main activity. Now I want to get an instance of the ViewModel in the main activity.
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Get ViewModel In New Way
MainActivityViewModel mainActivityViewModel;
mainActivityViewModel= new ViewModelProvider(this).get(MainActivityViewModel.class);
Use val viewModel by viewModels<TheViewModel>()
in Activities and val viewModel by activityViewModels<TheViewModel>()
in fragment to obtain the same viewmodel from the activity (so sharing the viewmodel).
This is part of androidx
now
ViewModel viewModel = ViewModelProviders.of(this).get(ViewModel.class);
Android Support library version is depreciated. So you need to make sure that you import Androidx. And you need to implement androidx dependency in Gradle file.
It is not advised to create a new ViewModel object with "new" keyword.
Duplicate question and already answered here
Simply replace:
This:
boardViewModel = ViewModelProviders.of(this).get(BoardViewModel::class.java)
With this:
boardViewModel = ViewModelProvider(this).get(BoardViewModel::class.java)
You can use a ViewModelFactory
:
val viewModelFactory = VMFactory(requireActivity().application)
viewModel= ViewModelProvider(requireActivity(),viewModelFactory).get(MainViewModel::class.java)
VMFactory code:
class VMFactory(application: Application) : ViewModelProvider.NewInstanceFactory() {
val _application: Application=application
@NonNull
override fun <T : ViewModel?> create(@NonNull modelClass: Class<T>): T {
return MainViewModel(_application) as T
}
}
Please note that here my MainViewModel
extends AndroidViewModel
and hence requires application as the input parameter.
I had similar problems and in the end found out I missed off the "extends ViewModel" within the class definition, so it should look like this:
public class ViewModelClass extends ViewModel
{
// Tracks the score for Team A
public int scoreTeamA = 0;
// Tracks the score for Team B
public int scoreTeamB = 0;
}