Get the most recent Friday's date SQL

Question

I\'m trying to get the most recent Friday in SQL Server 2008.

I have this. It gets the beginning of the week (monday) then subtracts 3 days to get Friday.

Answer 1

you can check if the current day of week is friday or greater DATEPART(dw,GETDATE()) and then call (SELECT DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0)+4) or (SELECT DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0)-3)

SELECT 
CASE WHEN DATEPART(dw,GETDATE()) >= 5 THEN 
(SELECT DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0)+4) 
ELSE 
(SELECT DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0)-3) 
END

Answer 2

The other solutions were not working for my use case.

This works for finding any previous day by replacing 'Sunday' with the day you`re looking for:

    DECLARE @myDate DATE = GETDATE()

    WHILE DATENAME(WEEKDAY, @myDate) <> 'Sunday'
    BEGIN
        SET @myDate = DATEADD(DAY, -1, @myDate)
    END

Answer 3

SELECT CONVERT(VARCHAR(12),GETDATE()) AS Today,
CASE WHEN (DATEPART(DW,GETDATE())< 7) 
THEN CONVERT(VARCHAR(12),(DATEADD(dd,-(DATEPART(DW,GETDATE())+1),GETDATE())))
ELSE CONVERT(VARCHAR(12),(DATEADD(d,- 1,GETDATE())))
END AS [Last Friday]

Answer 4

Here is a completly set oriented way to achive the last Friday:

select Friday from
(
select max(GetDate()) as Friday where datepart(dw, getdate()) = 6
union all
select max((GetDate() - 1)) where datepart(dw, (getdate() - 1)) = 6
union all
select max((GetDate() - 2)) where datepart(dw, (getdate() - 2)) = 6
union all
select max((GetDate() - 3)) where datepart(dw, (getdate() - 3)) = 6
union all
select max((GetDate() - 4)) where datepart(dw, (getdate() - 4)) = 6
union all
select max((GetDate() - 5)) where datepart(dw, (getdate() - 5)) = 6
) x where Friday is not null

Answer 5

This is what I got I hope it helps

DECLARE @UserDate DateTime
SET @UserDate = '2020-09-03'
SELECT DATEADD(day, (6 - datepart(weekday, @UserDate)) , @UserDate)

Answer 6

DECLARE @date DATETIME = '20110512' -- Thursday
SELECT DATEADD(DAY,-(DATEDIFF(DAY,'19000105',@date)%7),@date) --20110506

SET @date = '20110513' -- Friday
SELECT DATEADD(DAY,-(DATEDIFF(DAY,'19000105',@date)%7),@date) --20110513

SET @date = '20110514' -- Saturday
SELECT DATEADD(DAY,-(DATEDIFF(DAY,'19000105',@date)%7),@date) --20110513

1. Calculate the number of days between a known Friday (05 Jan 1900) and the given date
2. The remainder left from dividing the difference in 1. by 7 will be the days elapsed since the last Friday
3. Subtract the remainder in 2. from the given date