How to determine if compiling for 64-bit iOS in Xcode

Question

Consider the following function

CGSize CGSizeIntegral(CGSize size)
{
    return CGSizeMake(ceilf(size.width), ceilf(size.height));
}

CGSi

Answer 1

To determine if you are compiling for 64-bit, use __LP64__:

#if __LP64__
    return CGSizeMake(ceil(size.width), ceil(size.height));
#else
    return CGSizeMake(ceilf(size.width), ceilf(size.height));
#endif

__LP64__ stands for "longs and pointers are 64-bit" and is architecture-neutral.

According to your transition guide it applies for iOS as well:

The compiler defines the __LP64__ macro when compiling for the 64-bit runtime.

However, the preferred way to handle your use case is to use CGFLOAT_IS_DOUBLE. There is no guarantee that __LP64__ will always mean the CGFloat is a double, but it would be guaranteed with CGFLOAT_IS_DOUBLE.

#if CGFLOAT_IS_DOUBLE
    return CGSizeMake(ceil(size.width), ceil(size.height));
#else
    return CGSizeMake(ceilf(size.width), ceilf(size.height));
#endif

Answer 2

For Swift, and neglecting the OP's specific question involving CGFloats, etc., the following may be more swiftish:

  #if (arch(i386) || arch(arm))
     ....  // For 32-bit systems
  #else
     ....  // For 64-bit systems
  #endif


  #if (arch(x86_64) || arch(arm64))
     ....  // For 64-bit systems
  #endif

On the other hand, the compile-time constants discussed in the above answer are also available in Swift, if they are preferred.

This is mostly copied from here: https://stackoverflow.com/a/24869607/253938

And the Apple docs about these Swift compile-time constants is here: https://developer.apple.com/library/content/documentation/Swift/Conceptual/BuildingCocoaApps/InteractingWithCAPIs.html (at the very bottom of the page).