Oracle Age calculation from Date of birth and Today

Question

I want to calculate the current Age from Date of Birth in my Oracle function.

What I am using is (Today-Dob)/30/12, but this is not accurate as some mon

Answer 1

You can try below method,

SELECT EXTRACT(YEAR FROM APP_SUBMITTED_DATE)-EXTRACT(YEAR FROM BIRTH_DATE) FROM SOME_TABLE;

It will compare years and give age accordingly.
You can also use SYSDATE instead of APP_SUBMITTED_DATE.

Regards.

Answer 2

For business logic I usually find a decimal number (in years) is useful:

select months_between(TRUNC(sysdate),
                      to_date('15-Dec-2000','DD-MON-YYYY')
                     )/12
as age from dual;

       AGE
----------
9.48924731

Answer 3

SQL> select trunc(months_between(sysdate,dob)/12) year,
  2         trunc(mod(months_between(sysdate,dob),12)) month,
  3         trunc(sysdate-add_months(dob,trunc(months_between(sysdate,dob)/12)*12+trunc(mod(months_between(sysdate,dob),12)))) day
  4  from (Select to_date('15122000','DDMMYYYY') dob from dual);

      YEAR      MONTH        DAY
---------- ---------- ----------
         9          5         26

SQL>

Answer 4

Suppose that you want to have the age (number of years only, a fixed number) of someone born on June 4, 1996, execute this command :

SELECT TRUNC(TO_NUMBER(SYSDATE - TO_DATE('04-06-1996')) / 365.25) AS AGE FROM DUAL;

Result : (Executed May 28, 2019)

       AGE
----------
        22

Explanation :

• SYSDATE : Get system's (OS) actual date.
• TO_DATE('04-06-1996') : Convert VARCHAR (string) birthdate into DATE (SQL type).
• TO_NUMBER(...) : Convert a date to NUMBER (SQL type)
• Devide per 365.25 : To have a bissextile year every four years (4 * 0.25 = 1 more day).
• Trunc(...) : Retrieve the entire part only from a number.

Answer 5

SELECT 
TRUNC((SYSDATE - TO_DATE(DOB, 'YYYY-MM-DD'))/ 365.25) AS AGE_TODAY FROM DUAL;

This is easy and straight to the point.

Answer 6

Or how about this?

with some_birthdays as
( 
    select date '1968-06-09' d from dual union all
    select date '1970-06-10' from dual union all
    select date '1972-06-11' from dual union all
    select date '1974-12-11' from dual union all
    select date '1976-09-17' from dual
)
select trunc(sysdate) today
, d birth_date
, floor(months_between(trunc(sysdate),d)/12) age
from some_birthdays;