The script has to verify if one predefined IP is present in a big array of IPs. Currently I code that function like this (saying that \"ips\" is my array of IP and \"ip\" is the
You could use the Array#include method to return you a true/false.
http://ruby-doc.org/core-1.9.3/Array.html#method-i-include-3F
if ips.include?(ip) #=> true
puts 'ip exists'
else
puts 'ip doesn\'t exist'
end
ips = ['10.10.10.10','10.10.10.11','10.10.10.12']
ip = '10.10.10.10'
ips.include?(ip) => true
ip = '10.10.10.13'
ips.include?(ip) => false
check Documentaion here
have you tried the Array#include? function?
http://ruby-doc.org/core-1.9.3/Array.html#method-i-include-3F
You can see from the source it does almost exactly the same thing, except natively.
A faster way would be:
if ips.include?(ip)
puts "ip exists"
return 1
else
puts "ip doesn't exist"
return nil
end
You can use Set. It is implemented on top of Hash and will be faster for big datasets - O(1).
require 'set'
s = Set.new ['1.1.1.1', '1.2.3.4']
# => #<Set: {"1.1.1.1", "1.2.3.4"}>
s.include? '1.1.1.1'
# => true