Fastest way to find a String into an array of string

Question

The script has to verify if one predefined IP is present in a big array of IPs. Currently I code that function like this (saying that \"ips\" is my array of IP and \"ip\" is the

Answer 1

ips = ['10.10.10.10','10.10.10.11','10.10.10.12']

ip = '10.10.10.10'
ips.include?(ip) => true

ip = '10.10.10.13'
ips.include?(ip) => false

check Documentaion here

Answer 2

A faster way would be:

if ips.include?(ip)
  puts "ip exists"
  return 1
else
  puts "ip doesn't exist"
  return nil
end

Answer 3

You can use Set. It is implemented on top of Hash and will be faster for big datasets - O(1).

require 'set'
s = Set.new ['1.1.1.1', '1.2.3.4']
# => #<Set: {"1.1.1.1", "1.2.3.4"}> 
s.include? '1.1.1.1'
# => true 

Answer 4

You could use the Array#include method to return you a true/false.

http://ruby-doc.org/core-1.9.3/Array.html#method-i-include-3F

if ips.include?(ip) #=> true
  puts 'ip exists'
else
  puts 'ip  doesn\'t exist'
end

Answer 5

have you tried the Array#include? function?

http://ruby-doc.org/core-1.9.3/Array.html#method-i-include-3F

You can see from the source it does almost exactly the same thing, except natively.