PHP: check if any posted vars are empty - form: all fields required

Question

Is there a simpler function to something like this:

if (isset($_POST[\'Submit\'])) {
    if ($_POST[\'login\'] == \"\" || $_POST[\'password\'] == \"\" || $_P         


        

Answer 1

Personally I extract the POST array and then have if(!$login || !$password) then echo fill out the form :)

Answer 2

Something like this:

// Required field names
$required = array('login', 'password', 'confirm', 'name', 'phone', 'email');

// Loop over field names, make sure each one exists and is not empty
$error = false;
foreach($required as $field) {
  if (empty($_POST[$field])) {
    $error = true;
  }
}

if ($error) {
  echo "All fields are required.";
} else {
  echo "Proceed...";
}

Answer 3

Note : Just be careful if 0 is an acceptable value for a required field. As @Harold1983- mentioned, these are treated as empty in PHP. For these kind of things we should use isset instead of empty.

$requestArr =  $_POST['data']// Requested data 
$requiredFields = ['emailType', 'emailSubtype'];
$missigFields = $this->checkRequiredFields($requiredFields, $requestArr);

if ($missigFields) {
    $errorMsg = 'Following parmeters are mandatory: ' . $missigFields;
    return $errorMsg;
}

// Function  to check whether the required params is exists in the array or not.
private function checkRequiredFields($requiredFields, $requestArr) {
    $missigFields = [];
    // Loop over the required fields and check whether the value is exist or not in the request params.
    foreach ($requiredFields as $field) {`enter code here`
        if (empty($requestArr[$field])) {
            array_push($missigFields, $field);
        }
    }
    $missigFields = implode(', ', $missigFields);
    return $missigFields;
}