Converting separate month, day and year values into a timestamp

Question

I have a month value (1-12), day value (1-31), and a year value (2010,2011,2012). I also have a hour value and a minute value.

How can I give this to strtotime()

Answer 1

why convert string to date when you already know year month and date.

use setDate funtion

<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>

Answer 2

Y-m-d hh:mm will work

echo strtotime('2011-12-14 11:44 am');

cit @Pekka :)

Answer 3

Given the variables $year $month $day $hour $minute you can do:

strtotime("$year-$month-$day $hour:$minute");

Be careful to enclose the variables with ", never in this case with '.

UPDATE (thanks to comments of @Clockwork and @Tadeck):

In case there is a variable $timeofday that represents the time of day (i.e. AM or PM), then you can parse it this with:

strtotime("$year-$month-$day $hour:$minute$timeofday");

that is to say, just attach that variable to the end of the text.

Answer 4

strtotime($month."-".$day."-".$year)

Answer 5

You can provide it to function strtotime() in many ways, as mentioned in documentation. Some examples include:

$your_time = strtotime('12/31/2011 9:59');
$your_time = strtotime('2011-12-31 9:59');
$your_time = strtotime('December 31, 2011 9:59');

etc. It really is very flexible.

You can find the list of valid formats in the documentation, and that is (from the "Compound Formats" list in the mentioned documentation) for example:

• 10/Oct/2000:13:55:36 -0700,
• 2008:08:07 18:11:31,
• 2008-08-07 18:11:31,
• 2008-07-01T22:35:17.02,
• 2008-07-01T22:35:17.03+08:00,
• 20080701T22:38:07,
• 20080701T9:38:07,
• 20080701t223807,
• 20080701T093807,
• 2008-7-1T9:3:37,

(this is really copy of the documentation)

Answer 6

Is strtotime the best tool for this job? What about mktime()?

$time = mktime($hour, $minute, 0, $month, $day, $year);