Golang: extract data with Regex

Question

I\'m trying to extract whatever data inside ${}.

For example, the data extracted from this string should be abc.

git commit -m          


        

Answer 1

You can try with this too,

re := regexp.MustCompile("\\$\\{(.*?)\\}")

str := "git commit -m '${abc}'"
res := re.FindAllStringSubmatch(str, 1)
for i := range res {
    //like Java: match.group(1)
    fmt.Println("Message :", res[i][1])
}

GoPlay: https://play.golang.org/p/PFH2oDzNIEi

Answer 2

Try re := regexp.MustCompile(\$\{(.*)\}) * is a quantifier, you need something to quantify. . would do as it matches everything.

Answer 3

You need to escape $, { and } in the regex.

re := regexp.MustCompile("\\$\\{(.*?)\\}")
match := re.FindStringSubmatch("git commit -m '${abc}'")
fmt.Println(match[1])

Golang Demo

In regex,

$ <-- End of string
{} <-- Contains the range. e.g. a{1,2}

You can also use

re := regexp.MustCompile(`\$\{([^}]*)\}`)

Answer 4

Because $, { and } all have special meaning in a regex and need to be backslashed to match those literal characters, because * doesn't work that way, and because you didn't actually include a capturing group for the data you want to capture. Try:

re := regexp.MustCompile(`\$\{.+?)\}`)