Check if class has method in PHP

Question

Currently my code looks like that:

switch ($_POST[\'operation\']) {
    case \'create\':
        $db_manager->create();
        break;
    case \'retrieve\':
         


        

Answer 1

You can use method_exists:

if (method_exists($db_manager, $_POST['operation'])){
  $db_manager->{$_POST['operation']}();
} else {
  echo 'error';
}

Though I strongly advise you don't go about programming this way...

Answer 2

Use method_exists()

method_exists($obj, $method_name);

Answer 3

You can use is_callable() or method_exists().

The difference between them is that the latter wouldn't work for the case, if __call() handles the method call.

Answer 4

You can use method_exists(). But this is a really bad idea

If $_POST['operation'] is set to some magic function names (like __set()), your code will still explode. Better use an array of allowed function names.