How to remove all duplicate items from a list [duplicate]

Answer 1

This should do it for you:

new_list = list(set(old_list))

set will automatically remove duplicates. list will cast it back to a list.

Answer 2

It's because you are missing a capital letter, actually.

Purposely dedented:

for i in lseparatedOrbList:   # capital 'L'
for j in lseparatedOrblist:   # lowercase 'l'

Though the more efficient way to do it would be to insert the contents into a set.

If maintaining the list order matters (ie, it must be "stable"), check out the answers on this question

Answer 3

Use set():

woduplicates = set(lseparatedOrblist)

Returns a set without duplicates. If you, for some reason, need a list back:

woduplicates = list(set(lseperatedOrblist))

This will, however, have a different order than your original list.

Answer 4

Just make a new list to populate, if the item for your list is not yet in the new list input it, else just move on to the next item in your original list.

for i in mylist:
  if i not in newlist:
    newlist.append(i)

I think this is the correct syntax, but my python is a bit shaky, I hope you at least get the idea.

Answer 5

for unhashable lists. It is faster as it does not iterate about already checked entries.

def purge_dublicates(X):
    unique_X = []
    for i, row in enumerate(X):
        if row not in X[i + 1:]:
            unique_X.append(row)
    return unique_X