Suppose I have the following:
df = pd.DataFrame({\'a\':range(2), \'b\':range(2), \'c\':range(2), \'d\':range(2)})
I\'d like to \"pop\" two colu
Here's an alternative, but I'm not sure if it's more classy than your original solution:
df2 = pd.DataFrame([df.pop(x) for x in ['c', 'd']]).T
df3 = pd.DataFrame([df.pop(x) for x in ['a', 'b']]).T
Output:
print(df2)
# c d
#0 0 0
#1 1 1
print(df3)
# a b
#0 0 0
#1 1 1
This will have to be a two step process (you cannot get around this, because as rightly mentioned, pop
works for a single column and returns a Series).
First, slice df
(step 1), and then drop those columns (step 2).
df2 = df[['c', 'd']].copy()
df = df.drop(['c', 'd'], axis=1)
And here's the ugly alternative using pd.concat
:
df2 = pd.concat([df.pop(x) for x in ['c', 'd']], axis=1)
This is still a two step process, but you're doing it in one line.
df
a b
0 0 0
1 1 1
df2
c d
0 0 0
1 1 1
With that said, I think there's value in allowing pop
to take a list-like of column headers appropriately returning a DataFrame of popped columns. This would make a good feature request for GitHub, assuming one has the time to write one up.