Aggregate function in SQL WHERE-Clause

Question

In a test at university there was a question; is it possible to use an aggregate function in the SQL WHERE clause.

I always thought this isn\'t possibl

Answer 1

SELECT COUNT( * )   
FROM agents   
HAVING COUNT(*)>3;  

See more below link:

• http://www.w3resource.com/sql/aggregate-functions/count-having.php#sthash.90csRM4I.dpuf][1] call me if any query:85110 51548

• http://www.w3resource.com/sql/aggregate-functions/count-having.php

Answer 2

HAVING is like WHERE with aggregate functions, or you could use a subquery.

select EmployeeId, sum(amount)
from Sales
group by Employee
having sum(amount) > 20000

Or

select EmployeeId, sum(amount)
from Sales
group by Employee
where EmployeeId in (
    select max(EmployeeId) from Employees)

Answer 3

Another solution is to Move the aggregate fuction to Scalar User Defined Function

Create Your Function:

CREATE FUNCTION getTotalSalesByProduct(@ProductName VARCHAR(500))
RETURNS INT
AS
BEGIN

DECLARE @TotalAmount INT

SET @TotalAmount = (select SUM(SaleAmount) FROM Sales where Product=@ProductName)

RETURN @TotalAmount

END

Use Function in Where Clause

SELECT ProductName, SUM(SaleAmount) AS TotalSales
FROM Sales
WHERE dbo.getTotalSalesByProduct(ProductName)  > 1000
GROUP BY Product

References:

1. 2.

Hope helps someone.

Answer 4

You can't use an aggregate directly in a WHERE clause; that's what HAVING clauses are for.

You can use a sub-query which contains an aggregate in the WHERE clause.

Answer 5

UPDATED query:

select id from t where id < (select max(id) from t);

It'll select all but the last row from the table t.

Answer 6

You haven't mentioned the DBMS. Assuming you are using MS SQL-Server, I've found a T-SQL Error message that is self-explanatory:

"An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference"

http://www.sql-server-performance.com/

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And an example that it is possible in a subquery.

Show all customers and smallest order for those who have 5 or more orders (and NULL for others):

SELECT a.lastname
     , a.firstname
     , ( SELECT MIN( o.amount )
         FROM orders o
         WHERE a.customerid = o.customerid
           AND COUNT( a.customerid ) >= 5
        )
        AS smallestOrderAmount
FROM account a
GROUP BY a.customerid
       , a.lastname
       , a.firstname ;

---

UPDATE.

The above runs in both SQL-Server and MySQL but it doesn't return the result I expected. The next one is more close. I guess it has to do with that the field customerid, GROUPed BY and used in the query-subquery join is in the first case PRIMARY KEY of the outer table and in the second case it's not.

Show all customer ids and number of orders for those who have 5 or more orders (and NULL for others):

SELECT o.customerid
     , ( SELECT COUNT( o.customerid )
         FROM account a
         WHERE a.customerid = o.customerid
           AND COUNT( o.customerid ) >= 5
        )
        AS cnt
FROM orders o
GROUP BY o.customerid ;