Why does SELECT results differ between mysql and sqlite?

Question

I\'m re-asking this question in a simplified and expanded manner.

Consider these sql statements:

create table foo (id INT, score INT);

insert into foo v         


        

Answer 1

Lets look at this two ways, i'll use postgres 9.0 as my reference database

(1)

-- select rows from foo 

select T1.id, avg(T1.score) avg1
from foo T1
group by T1.id
-- where we don't have any rows from T2
having  not exists (
-- select rows from foo
select T2.id, avg(T2.score) avg2
from foo T2
group by T2.id
-- where the average score for any row is greater than the average for 
-- any row in T1
having avg2 > avg1);

 id  |        avg1        
-----+--------------------
 106 | 4.5000000000000000
(1 row)

then let's move some of the logic inside the subquery, getting rid of the 'not' : (2)

-- select rows from foo 
select T1.id, avg(T1.score) avg1
from foo T1
group by T1.id
-- where we do have rows from T2
having  exists (
-- select rows from foo
select T2.id, avg(T2.score) avg2
from foo T2
group by T2.id
-- where the average score is less than or equal than the average for any row in T1
having avg2 <= avg1);
-- I think this expression will be true for all rows as we are in effect doing a
--cartesian join 
-- with the 'having' only we don't display the cartesian row set

 id  |        avg1        
-----+--------------------
 106 | 4.5000000000000000
 107 | 4.0000000000000000
(2 rows)

so you have got to ask yourself -- what do you actually mean when you do this correlated subquery inside a having clause, if it evaluates every row against every row from the primary query we are making a cartesian join and I don't think we should be pointing fingers at the SQL engine.

if you want every row that is less than the maximum average What you should be saying is:

select T1.id, avg(T1.score) avg1 
from foo T1 group by T1.id
having avg1 not in 
(select max(avg1) from (select id,avg(score) avg1 from foo group by id)) 

Answer 2

Have you tried this version? :

select T1.id, avg(T1.score) avg1
from foo T1
group by T1.id
having not exists (
    select T2.id, avg(T2.score) avg2
    from foo T2
    group by T2.id
    having avg(T2.score) > avg(T1.score));

---

Also this one (which should be giving same results):

select T1.*
from
  ( select id, avg(score) avg1
    from foo 
    group by id
  ) T1
where not exists (
    select T2.id, avg(T2.score) avg2
    from foo T2
    group by T2.id
    having avg(T2.score) > avg1);

---

The query can also be handled with derived tables, instead of subquery in HAVING clause:

select ta.id, ta.avg1
from 
  ( select id, avg(score) avg1
    from foo
    group by id
  ) ta
  JOIN
  ( select avg(score) avg1
    from foo 
    group by id
    order by avg1 DESC
    LIMIT 1
  ) tmp
  ON tmp.avg1 = ta.avg1 

Answer 3

I tried to mess with some variants of query.

It seems, like sqlite has errors in using of previous declared fields in a nested HAVING expressions.

In your example avg1 under second having is always equal to 5.0

Look:

select T1.id, avg(T1.score) avg1
from foo T1
group by T1.id
having not exists (
    SELECT 1 AS col1 GROUP BY col1 HAVING avg1 = 5.0);

This one returns nothing, but execution of the following query returns both records:

...
having not exists (
    SELECT 1 AS col1 GROUP BY col1 HAVING avg1 <> 5.0);

I can not find any similar bug at sqlite tickets list.