Call Constructor Base after Code Execution

Question

Let say we have Class A and Class B. ClassB extends Class A. (ClassB : ClassA)

Now let\'s say that whenever I instantiate ClassB, I\'d like to Run some Random code and o

Answer 1

You can not call base constructor. But a different thing is that when you declare an object of derived class both constructor derived and base is called.

    class ClassA
{
    public ClassA()
    {
        Console.WriteLine("Initialization");
    }  
}

class ClassB : ClassA
{
    public ClassB() //: base() 
    {
        // Using :base() as commented above, I would execute ClassA ctor before                                                         //          Console.WriteLine as it is below this line... 
        Console.WriteLine("Before new");
        //base() //Calls ClassA constructor using inheritance
        //Run some more Codes here...
    }
}
void main(string[] args)
    {
      ClassB b = new ClassB();

    }

Answer 2

C# doesn't allow calling base constructors inside constructor bodies, different from Java.

Answer 3

I had the same problem. I found this solution to be the best if you don't have access to the base class.

public class BaseClass
{
    public BaseClass(string someValue)
    {
        Console.WriteLine(someValue);
    }
}

public class MyClass : BaseClass
{
    private MyClass(string someValue)
        : base(someValue)
    {
    }

    public static MyClass GetNewInstance(string someValue, bool overrideValue = false)
    {
        if (overrideValue)
        {
            someValue = "42";
        }
        return new MyClass(someValue);
    }
}

Answer 4

You can't do that with C#. Your best bet is to extract that code into it's own method in the parent and then call that from the child when you're ready.

Answer 5

Another hack if you can get away with calling a static method.

public class ClassA
{
    public ClassA()
    {
        Debug.WriteLine("Call A Constructor");
    }
}

public class ClassB:ClassA
{
    public ClassB():this(aMethod())
    {
    }

    private ClassB(object empty):base()
    {
        Debug.WriteLine("Class B Second Constructor");
    }

    private static object aMethod()
    {
        Debug.WriteLine("Run me First");
        return null;
    }
}

Answer 6

There's a hacky way of doing it using an instance variable initializer:

using System;

class ClassA
{
    public ClassA()
    {
        Console.WriteLine("Initialization");
    }  
}

class ClassB : ClassA
{
    private readonly int ignoreMe = BeforeBaseConstructorCall();

    public ClassB()
    {
    }

    private static int BeforeBaseConstructorCall()
    {
        Console.WriteLine("Before new");
        return 0; // We really don't care
    }
}

class Test
{
    static void Main()
    {
        new ClassB();
    }    
}

The less hacky way of doing it is to rethink how you construct a ClassB to start with. Instead of having clients call the constructor directly, provide a static method for them to call:

public static ClassB CreateInstance()
{
    Console.WriteLine("Before initialization stuff");
    return new ClassB();
}