java.util.date to String using DateTimeFormatter

前端 未结 5 2064
抹茶落季
抹茶落季 2021-02-12 12:08

How can I convert a java.util.Date to String using

 DateTimeFormatter dateTimeFormatter = DateTimeFormat.forPattern(\"yyyy-MM-dd\'T\'H         


        
相关标签:
5条回答
  • 2021-02-12 12:52

    You can use the joda time formatter class:

    import org.joda.time.DateTime;
    import org.joda.time.DateTimeZone;
    import org.joda.time.format.DateTimeFormat;
    import org.joda.time.format.DateTimeFormatter;
    # conflict with import java.time.format.DateTimeFormatter;
    
    final DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss")
                .withZone(DateTimeZone.UTC);
    
        System.out.println(DateTime.now().toString(formatter));
    
    0 讨论(0)
  • 2021-02-12 13:03

    since I asume you are using joda API: ergo, DateTimeFormatter is comming from org.joda.time.format.DateTimeFormatter:

     String dateTime = "02-13-2017 18:20:30";
    // Format for input
    DateTimeFormatter dtf = DateTimeFormat.forPattern("MM-dd-yyyy HH:mm:ss");
    // Parsing the date
    DateTime jodatime = dtf.parseDateTime(dateTime);
    
    System.out.println(jodatime );
    
    0 讨论(0)
  • 2021-02-12 13:04

    If you are using Java 8, you should not use java.util.Date in the first place (unless you receive the Date object from a library that you have no control over).

    In any case, you can convert a Date to a java.time.Instant using:

    Date date = ...;
    Instant instant = date.toInstant();
    

    Since you are only interested in the date and time, without timezone information (I assume everything is UTC), you can convert that instant to a LocalDateTime object:

    LocalDateTime ldt = instant.atOffset(ZoneOffset.UTC).toLocalDateTime();
    

    Finally you can print it with:

    DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss");
    System.out.println(ldt.format(fmt));
    

    Or use the predefined formatter, DateTimeFormatter.ISO_LOCAL_DATE_TIME.

    System.out.println(ldt.format(DateTimeFormatter.ISO_LOCAL_DATE_TIME));
    

    Note that if you don't provide a formatter, calling ldt.toString gives output in standard ISO 8601 format (including milliseconds) - that may be acceptable for you.

    0 讨论(0)
  • 2021-02-12 13:05
    DateTime dt = new DateTime(date);
    DateTimeFormatter dtf = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss");
    dt.toString(dtf)
    
    0 讨论(0)
  • 2021-02-12 13:13
    DateTimeFormatterOBJECT=DateTimeFormatter.ofPattern("DD/MMM/YYYY HH//MM/SS");
    
    String MyDateAndTime= LocalDate.now().format(DateTimeFormatterOBJECT);
    
    0 讨论(0)
提交回复
热议问题