Get Random Color [duplicate]

Answer 1

The original version of your last method (pre-Edit) will return all different sorts of colors. I would be sure to use a single Random object rather than create a new one each time:

Random r = new Random();
private void button6_Click(object sender, EventArgs e)
{
    pictureBox1.BackColor = Color.FromArgb(r.Next(0, 256), 
         r.Next(0, 256), r.Next(0, 256));

    Console.WriteLine(pictureBox1.BackColor.ToString());
}

It produces all sorts of different colors:

Color [A=255, R=241, G=10, B=200]
Color [A=255, R=41, G=125, B=132]
Color [A=255, R=221, G=169, B=109]
Color [A=255, R=228, G=152, B=197]
Color [A=255, R=50, G=153, B=103]
Color [A=255, R=92, G=236, B=162]
Color [A=255, R=52, G=103, B=204]
Color [A=255, R=197, G=126, B=133]

Answer 2

Here's the answer I started posting before you deleted and then un-deleted your question:

public partial class Form1 : Form
{
    private Random rnd = new Random();

    public Form1()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {  
        Color randomColor = Color.FromArgb(rnd.Next(256), rnd.Next(256), rnd.Next(256));

        BackColor = randomColor;
    }
}