Django - How to pass several arguments to the url template tag

Question

In my urls.py I have:

(r\'^(?P\\d{4})/(?P\\d{2})/(?P\\d{2})/section/(?P[-\\w]+)/$\', 
    \'paper.views.issue_sec         


        

Answer 1

Your month expression is (?P<month>\d{2}), but you're sending it the argument 1. The 1 doesn't match \d{2}, so the url resolver isn't finding your view.

Try changing the month expression to \d{1,2} (or something to that effect).

Answer 2

I had the same issue (I'm using Django 1.3.1) and tried Gregor Müllegger's suggestion, but that didn't work for two reasons:

• there should be no commas between year, month and day values
• my class-based generic view seems to take only keyword arguments

Thus the only working solution was:

{% url news_detail slug=object.slug year=object.date|date:"Y" month=object.date|date:"m" day=object.date|date:"d" %}

Answer 3

The problem lives in the /(?P<month>\d{2})/ part of your url configuration. It only allows exactly two digits (\d{2}) while issue.pub_date.month is only one digit.

You can do either allow also one digit in the URL (but this will violate the principle of unique URLs, /2010/1/... would be the same as /2010/01/...) or pass two digits to the month argument in your url templatetag.
You can use the date filter to achieve a consistent formating of date objects. Use the url tag like this:

{% url paper_issue_section_detail issue.pub_date|date:"Y",issue.pub_date|date:"m",issue.pub_date|date:"d",section_li.slug %}

Look at the month and day argument: It will be always displayed as two digits (with a leading zero if necessary). Have a look at the documentation of the now tag to see which options are possible for the date filter.