LINQ's Distinct() on a particular property

Question

I am playing with LINQ to learn about it, but I can\'t figure out how to use Distinct when I do not have a simple list (a simple list of integers is pretty easy

Answer 1

Use:

List<Person> pList = new List<Person>();
/* Fill list */

var result = pList.Where(p => p.Name != null).GroupBy(p => p.Id).Select(grp => grp.FirstOrDefault());

The where helps you filter the entries (could be more complex) and the groupby and select perform the distinct function.

Answer 2

List<Person>lst=new List<Person>
        var result1 = lst.OrderByDescending(a => a.ID).Select(a =>new Player {ID=a.ID,Name=a.Name} ).Distinct();

Answer 3

What if I want to obtain a distinct list based on one or more properties?

Simple! You want to group them and pick a winner out of the group.

List<Person> distinctPeople = allPeople
  .GroupBy(p => p.PersonId)
  .Select(g => g.First())
  .ToList();

If you want to define groups on multiple properties, here's how:

List<Person> distinctPeople = allPeople
  .GroupBy(p => new {p.PersonId, p.FavoriteColor} )
  .Select(g => g.First())
  .ToList();

Answer 4

Override Equals(object obj) and GetHashCode() methods:

class Person
{
    public int Id { get; set; }
    public int Name { get; set; }

    public override bool Equals(object obj)
    {
        return ((Person)obj).Id == Id;
        // or: 
        // var o = (Person)obj;
        // return o.Id == Id && o.Name == Name;
    }
    public override int GetHashCode()
    {
        return Id.GetHashCode();
    }
}

and then just call:

List<Person> distinctList = new[] { person1, person2, person3 }.Distinct().ToList();

Answer 5

Please give a try with below code.

var Item = GetAll().GroupBy(x => x .Id).ToList();

Answer 6

The following code is functionally equivalent to Jon Skeet's answer.

Tested on .NET 4.5, should work on any earlier version of LINQ.

public static IEnumerable<TSource> DistinctBy<TSource, TKey>(
  this IEnumerable<TSource> source, Func<TSource, TKey> keySelector)
{
  HashSet<TKey> seenKeys = new HashSet<TKey>();
  return source.Where(element => seenKeys.Add(keySelector(element)));
}

Incidentially, check out Jon Skeet's latest version of DistinctBy.cs on Google Code.