unicode string equivalent of contain

Question

I have an error when trying to use contain in python.

s = u\"some utf8 words\"
k = u\"one utf8 word\"

if s.contains(k):
    print \"contains\" 

Answer 1

The same for ascii and utf8 strings:

if k in s:
    print "contains" 

There is no contains() on either ascii or uft8 strings:

>>> "strrtinggg".contains
AttributeError: 'str' object has no attribute 'contains'

---

What you can use instead of contains is find or index:

if k.find(s) > -1:
    print "contains"

or

try:
    k.index(s)
except ValueError:
    pass  # ValueError: substring not found
else:
    print "contains"

But of course, the in operator is the way to go, it's much more elegant.

Answer 2

Strings don't have "contain" attribute.

s = "haha i am going home"
s_new = s.split(' ')
k = "haha"

if k in s_new:
    print "contains"

I guess you want to achieve this

Answer 3

There is no difference between str and unicode.

print u"ábc" in u"some ábc"
print "abc" in "some abc"

is basically the same.

Answer 4

Testing of string existance in string

string = "Little bear likes beer"
if "beer" in string:
    print("Little bear likes beer")
else:
    print("Little bear is driving")