I understand that when you declare a variable in Typescript, you can choose whether or not to specify a type for the variable. If no type is specified, the default \"any\" type
You could also set in your tsconfig.json
:
{
"compilerOptions": {
"noImplicitReturns": true,
"noImplicitAny": true
}
}
It's not true that a variable declared is necessarily without type in TypeScript. The TypeScript compiler will, when possible, infer a type based on the right hand side of a declaration.
For example:
var x = 150;
x
will be a Number as the RHS is a number.
You can use the command line compile option to catch declarations where the type cannot be inferred by using --noImplicitAny
:
Warn on expressions and declarations with an implied 'any' type.
This option would catch a case where a variable d
for example is declared, yet not assigned to a value immediately.
var d;
Will produce an error:
error TS7006: Parameter 'd' of 'test' implicitly has an 'any' type.
The compiler switch also catches parameters without a specified type, and as @basarat pointed out in a comment, it also catches return types and class/interface members.
There's a little more information in this blog post as well. Note that there's also an equivalent MSBuild/project setting available: <TypeScriptNoImplicitAny>
.