dnspython will do my DNS lookups very nicely, but it entirely ignores the contents of /etc/hosts
.
Is there a python library call which will do the right
list( map( lambda x: x[4][0], socket.getaddrinfo( \
'www.example.com.',22,type=socket.SOCK_STREAM)))
gives you a list of the addresses for www.example.com. (ipv4 and ipv6)
I found this way to expand a DNS RR hostname that expands into a list of IPs, into the list of member hostnames:
#!/usr/bin/python
def expand_dnsname(dnsname):
from socket import getaddrinfo
from dns import reversename, resolver
namelist = [ ]
# expand hostname into dict of ip addresses
iplist = dict()
for answer in getaddrinfo(dnsname, 80):
ipa = str(answer[4][0])
iplist[ipa] = 0
# run through the list of IP addresses to get hostnames
for ipaddr in sorted(iplist):
rev_name = reversename.from_address(ipaddr)
# run through all the hostnames returned, ignoring the dnsname
for answer in resolver.query(rev_name, "PTR"):
name = str(answer)
if name != dnsname:
# add it to the list of answers
namelist.append(name)
break
# if no other choice, return the dnsname
if len(namelist) == 0:
namelist.append(dnsname)
# return the sorted namelist
namelist = sorted(namelist)
return namelist
namelist = expand_dnsname('google.com.')
for name in namelist:
print name
Which, when I run it, lists a few 1e100.net hostnames:
The normal name resolution in Python works fine. Why do you need DNSpython for that. Just use socket's getaddrinfo
which follows the rules configured for your operating system (on Debian, it follows /etc/nsswitch.conf
:
>>> print socket.getaddrinfo('google.com', 80)
[(10, 1, 6, '', ('2a00:1450:8006::63', 80, 0, 0)), (10, 2, 17, '', ('2a00:1450:8006::63', 80, 0, 0)), (10, 3, 0, '', ('2a00:1450:8006::63', 80, 0, 0)), (10, 1, 6, '', ('2a00:1450:8006::68', 80, 0, 0)), (10, 2, 17, '', ('2a00:1450:8006::68', 80, 0, 0)), (10, 3, 0, '', ('2a00:1450:8006::68', 80, 0, 0)), (10, 1, 6, '', ('2a00:1450:8006::93', 80, 0, 0)), (10, 2, 17, '', ('2a00:1450:8006::93', 80, 0, 0)), (10, 3, 0, '', ('2a00:1450:8006::93', 80, 0, 0)), (2, 1, 6, '', ('209.85.229.104', 80)), (2, 2, 17, '', ('209.85.229.104', 80)), (2, 3, 0, '', ('209.85.229.104', 80)), (2, 1, 6, '', ('209.85.229.99', 80)), (2, 2, 17, '', ('209.85.229.99', 80)), (2, 3, 0, '', ('209.85.229.99', 80)), (2, 1, 6, '', ('209.85.229.147', 80)), (2, 2, 17, '', ('209.85.229.147', 80)), (2, 3, 0, '', ('209.85.229.147', 80))]
This code works well for returning all of the IP addresses that might belong to a particular URI. Since many systems are now in a hosted environment (AWS/Akamai/etc.), systems may return several IP addresses. The lambda was "borrowed" from @Peter Silva.
def get_ips_by_dns_lookup(target, port=None):
'''
this function takes the passed target and optional port and does a dns
lookup. it returns the ips that it finds to the caller.
:param target: the URI that you'd like to get the ip address(es) for
:type target: string
:param port: which port do you want to do the lookup against?
:type port: integer
:returns ips: all of the discovered ips for the target
:rtype ips: list of strings
'''
import socket
if not port:
port = 443
return list(map(lambda x: x[4][0], socket.getaddrinfo('{}.'.format(target),port,type=socket.SOCK_STREAM)))
ips = get_ips_by_dns_lookup(target='google.com')
The answer above was meant for Python 2. If you're using Python 3, here is the code.
>>> import socket
>>> print(socket.gethostbyname('google.com'))
8.8.8.8
>>>
I'm not really sure if you want to do DNS lookups yourself or if you just want a host's ip. In case you want the latter,
import socket
print(socket.gethostbyname('localhost')) # result from hosts file
print(socket.gethostbyname('google.com')) # your os sends out a dns query