I have a matrix (32X48).
How can I convert the matrix into a single dimensional array?
If we're talking about data.frame, then you should ask yourself are the variables of the same type? If that's the case, you can use rapply, or unlist, since data.frames are lists, deep down in their souls...
data(mtcars)
unlist(mtcars)
rapply(mtcars, c) # completely stupid and pointless, and slower
You can use Joshua's solution but I think you need Elts_int <- as.matrix(tmp_int)
Or for loops:
z <- 1 ## Initialize
counter <- 1 ## Initialize
for(y in 1:48) { ## Assuming 48 columns otherwise, swap 48 and 32
for (x in 1:32) {
z[counter] <- tmp_int[x,y]
counter <- 1 + counter
}
}
z is a 1d vector.
From ?matrix
: "A matrix is the special case of a two-dimensional 'array'." You can simply change the dimensions of the matrix/array.
Elts_int <- as.matrix(tmp_int) # read.table returns a data.frame as Brandon noted
dim(Elts_int) <- (maxrow_int*maxcol_int,1)
It might be so late, anyway here is my way in converting Matrix to vector:
library(gdata)
vector_data<- unmatrix(yourdata,byrow=T))
hope that will help
try c()
x = matrix(1:9, ncol = 3)
x
[,1] [,2] [,3]
[1,] 1 4 7
[2,] 2 5 8
[3,] 3 6 9
c(x)
[1] 1 2 3 4 5 6 7 8 9
Either read it in with 'scan', or just do as.vector() on the matrix. You might want to transpose the matrix first if you want it by rows or columns.
> m=matrix(1:12,3,4)
> m
[,1] [,2] [,3] [,4]
[1,] 1 4 7 10
[2,] 2 5 8 11
[3,] 3 6 9 12
> as.vector(m)
[1] 1 2 3 4 5 6 7 8 9 10 11 12
> as.vector(t(m))
[1] 1 4 7 10 2 5 8 11 3 6 9 12