How to define a method in Scala that returns a Java object?

后端 未结 1 1365
北海茫月
北海茫月 2021-02-12 07:11

I want to define a private method in scala singleton class that looks like;

private def  createDomNode(tag: String, attrs: Map[String , String]): DomNode  {

}
<         


        
相关标签:
1条回答
  • 2021-02-12 08:04

    You should just put =:

    private def createDomNode(tag: String, attrs: Map[String , String]): DomNode = {
        // ...
    }
    

    If you will not put = between method signature and body, then return type is Unit, so this:

    def m(i: Int) {}
    

    is the same as

    def m(i: Int): Unit = {}
    

    Response to the comment: What I described earlier is actually method, if you define it within object, class or trait definition. Function syntax would look like this:

    val createDomNode: (String, Map[String , String]) => DomNode = { (tag, attrs) =>
        // ...
    }
    

    As You can see I define val with name createDomNode of function type. It can also be written like:

    val createDomNode: Function2[String, Map[String , String], DomNode] = { (tag, attrs) =>
        // ...
    }
    

    here is another example. In this case I define method that generates new function each time you call it:

    def createDomNode = (tag: String, attrs: Map[String , String]) => new DomNode
    

    But it's important to understand, that method returns a "function that returns DomNode" in this case, but not DomNode itself.


    About Programming in Scala reference. I think you are talking about Chapter 2 - Step 3 (in the intro)

    As you can see max function is defined in REPL, and it's really function. Actually you can also write something like this:

    class MyClass {
        def myMethod(i: Int): Int = {
            def myInnerFn(x: Int) = x * x
    
            myInnerFn(i)
        }
    }
    

    In this case myMethod is method and myInnerFn is function. So as you can see, it highly depends on the context. I believe this syntax for myInnerFn is just syntactic sugar for (I need to look in spec in order to say for sure):

    val myInnerFn = (x: Int) => x * x
    

    The same happens in REPL. And by the way that's because I wrote at the beginning:

    if you define it within object, class or trait definition

    Sorry, I need to be more clear about this and describe it in more detail in my second update.


    I looked in Scala spec. Seems that I'm not totally correct when I say that myInnerFn is syntactic sugar for the function. but seems that it's called Method Type. You can find it in spec section 3.3.1 Method Type:

    http://www.scala-lang.org/docu/files/ScalaReference.pdf

    hope it will give you some clue, if you want to dive deeper in this. I think it's easy to get lost in terminology. You can function in 2 contexts. In first we have

    • Function - returns some value
    • Procedure - returns no value (or in Scala context it returns Unit)

    And in second context:

    • Function - executable piece of code that can be passes around and treated as value
    • Method - belongs to the class

    And it's sometimes not clear in what context it meant. For example I can tell you that myMethod is as function just because it has return value (or in other words: myMethod it's not procedure). I believe it's the same case in book.


    One more thing. Sections 8.1, 8.2, 8.3 from Programming in Scala can help you to understand this terminology. And if I'm correct in my assumptions, what you think as Function is called First-class function in the book (it's described in section 8.3).

    Hope this helps

    0 讨论(0)
提交回复
热议问题