I have a dataframe with counts of different items, in different years:
df <- data.frame(item = rep(c(\'a\',\'b\',\'c\'), 3),
year = rep(c
Using order
function,
transform(dat, x= ave(count,year,FUN=function(x) order(x,decreasing=T)))
item year count x
1 a 2010 1 3
2 b 2010 4 2
3 c 2010 6 1
4 a 2011 3 2
5 b 2011 8 1
6 c 2011 3 3
7 a 2012 5 3
8 b 2012 7 2
9 c 2012 9 1
EDIT
You can use plyr
here also:
ddply(dat,.(year),transform,x = order(count,decreasing=T))
While using the answers given by others, I found that the following performs faster than the transform and dyplr variants:
df$year.rank <- ave(count, year, FUN = function(x) rank(-x, ties.method = "first"))
Using dplyr you could do it as follows:
library(dplyr) # 0.4.1
df %>%
group_by(year) %>%
mutate(yrrank = row_number(-count))
#Source: local data frame [9 x 4]
#Groups: year
#
# item year count yrrank
#1 a 2010 1 3
#2 b 2010 4 2
#3 c 2010 6 1
#4 a 2011 3 2
#5 b 2011 8 1
#6 c 2011 3 3
#7 a 2012 5 3
#8 b 2012 7 2
#9 c 2012 9 1
It is the same as:
df %>%
group_by(year) %>%
mutate(yrrank = rank(-count, ties.method = "first"))
Note that the resulting data is still grouped by "year". If you want to remove the grouping you can simply extend the pipe with %>% ungroup()
.
There is a rank
function to help you with that:
transform(df,
year.rank = ave(count, year,
FUN = function(x) rank(-x, ties.method = "first")))
item year count year.rank
1 a 2010 1 3
2 b 2010 4 2
3 c 2010 6 1
4 a 2011 3 2
5 b 2011 8 1
6 c 2011 3 3
7 a 2012 5 3
8 b 2012 7 2
9 c 2012 9 1
data.table
version for practice:
library(data.table)
DT <- as.data.table(df)
DT[,yrrank:=rank(-count,ties.method="first"),by=year]
item year count yrrank
1: a 2010 1 3
2: b 2010 4 2
3: c 2010 6 1
4: a 2011 3 2
5: b 2011 8 1
6: c 2011 3 3
7: a 2012 5 3
8: b 2012 7 2
9: c 2012 9 1