How to count no of lines in text file and store the value into a variable using batch script?

Question

I want to count the no of lines in a text file and then the value has to be stored into a environment variable. The command to count the no of lines is

findstr /R         


        

Answer 1

You can also mark with a wildcard symbol * to facilitate group files to count.

Z:\SQLData>find /c /v "" FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_*.txt

Result

---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIFRS01_V1.TXT: 2041

---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIOST00_V1.TXT: 315938

---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_AVIFRS00_V1.TXT: 0

---------- FR_OP133_OCCURENCES_COUNT_PER_DOCUMENTS_CNTPTF00_V1.TXT: 277

Answer 2

In the below code, the variable name are SalaryCount and TaxCount

@ECHO OFF    
echo Process started, please wait...    
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Salary.txt"') do set SalaryCount=%%C    
echo Salary,%SalaryCount%
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Tax.txt"') do set TaxCount=%%C
echo Tax,%TaxCount%

Now if you need to output these values to a csv file, you could use the below code.

@ECHO OFF
cd "D:\CSVOutputPath\"
echo Process started, please wait...
echo FILENAME,FILECOUNT> SUMMARY.csv
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Salary.txt"') do set Count=%%C
echo Salary,%Count%>> SUMMARY.csv
for /f %%C in ('Find /V /C "" ^< "D:\Trial\Tax.txt"') do set Count=%%C
echo Tax,%Count%>> SUMMARY.csv

The > will overwrite the existing content of the file and the >> will append the new data to existing data. The CSV will be generated in D:\CSVOutputPath

Answer 3

You can pipe the output of type into find inside the in(…) clause of a for /f loop:

for /f %%A in ('
    type "%~dpf1" ^| find /c /v ""
') do set "lineCount=%%A"

But the pipe starts a subshell, which slows things down.

Or, you could redirect input from the file into find like so:

for /f %%A in ('
    find /c /v "" ^< "%~dpf1"
') do set "lineCount=%%A"

But this approach will give you an answer 1 less than the actual number of lines if the file ends with one or more blank lines, as teased out by the late foxidrive in counting lines in a file.

And then again, you could always try:

find /c /v "" example.txt

The trouble is, the output from the above command looks like this:

---------- EXAMPLE.TXT: 511

You could split the string on the colon to get the count, but there might be more than one colon if the filename had a full path.

Here’s my take on that problem:

for /f "delims=" %%A in ('
    find /c /v "" "%~1"
') do for %%B in (%%A) do set "lineCount=%%B"

This will always store the count in the variable.

Just one last little problem… find treats null characters as newlines. So if sneaky nulls crept into your text file, or if you want to count the lines in a Unicode file, this answer isn’t for you.

Answer 4

@Tony: You can even get rid of the type %file% command.

for /f "tokens=2 delims=:" %%a in ('find /c /v "" %_file%') do set /a _Lines=%%a

For long files this should be even quicker.