How we can build CFG for a context-free language

后端 未结 0 1651
余生分开走
余生分开走 2021-02-12 04:23

Build CFG for the following language: {a^i b^j c^k | j not equal to i + k}. I have already tried the following CFG, but it miss some cases.

S---> AB
A--->          


        
相关标签:
回答
  • 消灭零回复
提交回复
热议问题