First off, I apologise if this is a duplicate question. I found many similar ones, but none that directly address my question.
In preparation for an upcoming exam, I am
It may work in Java8
as the stress is on Effectively Final
which means once the value is assigned to jtf
it should not be changed after wards. As per Java doc:
A variable or parameter whose value is never changed after it is initialized is effectively final.
I guess you are compiling with Java 8. Here your jtf
variable is effectively final, so it compiles fine. A variable is effectively final if its value is never changed after you initialized it.
See also Local Classes:
However, starting in Java SE 8, a local class can access local variables and parameters of the enclosing block that are final or effectively final. A variable or parameter whose value is never changed after it is initialized is effectively final.
and
Accessing Local Variables of the Enclosing Scope, and Declaring and Accessing Members of the Anonymous Class
Like local classes, anonymous classes can capture variables; they have the same access to local variables of the enclosing scope:
An anonymous class has access to the members of its enclosing class.
An anonymous class cannot access local variables in its enclosing scope that are not declared as final or effectively final.
[...]
If you tried with:
javac -source 1.7 MyFile.java
you'll have your expected error.
.java:13: error: local variable jtf is accessed from within inner class; needs to be declared final
jtf.setText(evt.getLocationOnScreen().toString());
^
1 error
So the answer of the exam question is: it compiles only if you're using Java 8+.
Seems that your Eclipse IDE uses Java 7 compiler. To change this to Java 8 use Project->Properties->Java Compiler->Compiler compliance level.
Java 8 added the ability to access "effectively final" variables. The final
keyword is no longer required as long as a variable is never changed after it is initialized.