Python Namespace Packages in Python3

Question

The topic of namespace packages seems a bit confusing for the uninitiated, and it doesn\'t help that prior versions of Python have implemented it in a few different ways or that

Answer 1

This is a tough subject. All the -'s, _'s, and __init__.py's everywhere don't exactly make it easy on us.

First, I'll answer your questions:

With the __init__.py, which of these should I be using (if any)?

• __init__.py can be completely empty, it just needs to be in the correct place. Namely (pun) they should be in any subpackage containing python code (excluding setup.py.) Follow those rules and you should be fine.

With setup.py, do I still need to add the namespace_modules parameter, and if so, would I use namespace_modules=['org.common'], or namespace_modules=['org', 'common']?

• Nope! Only name= and packages=. However, note the format of the packages= arg compared against the directory structure.
• Here's the format of the package= arg:
• Here's the corresponding directory structure:

Could I forgo all of the above by just implementing this differently somehow? Perhaps something simpler or more "pythonic"?

• If you want to be able to install multiple features individually, but under the same top-level namespace, you're on the right track.

---

I'll spend the rest of this answer re-implementing your namespace package in native format:

I'll put all helpful documentation I've been able to find at the bottom of the post.

K so I'm going to assume you want native namespace packages. First let's look at the current structure of your 2 repos:

org_client_client1_mod1/
  setup.py
  mod1/
    __init__.py
    somefile.py

&

org_common_config/
  setup.py
  config/
    __init__.py
    someotherfile.py

This^ would be too easy!!!

To get what you want:

My brain isn't elastic enough to know if we can go 3-levels deep with namespace packages, but to do what you want, here's what I'm pretty sure you'd want to do:

org-client/
  setup.py
  org/
    client/
      client1/
        __init__.py
        mod1/
          __init__.py
          somefile.py

&

org-common-but-also-note-this-name-doesnt-matter/
  setup.py
  org/
    common/
      __init__.py
      config/
        __init__.py
        someotherfile.py

Basically then the key is going to be specifying the correct name= & packages= args to stuptools.setup() inside of each setup.py.

These are going to be:

name='org_client',
...
packages=['org.client']

&

name='org_common'
...
packages['org.common']

respectively.

Then just install each one with pip install . inside each top-level dir.

Installing the first one will give you access to the somefile.py module, and installing the second will give you access to someotherfile.py. It also won't get confused about you trying to install 2 packages named org in the same environment.

K so the most helpful section of the docs: https://packaging.python.org/guides/packaging-namespace-packages/#packaging-namespace-packages

And then here's how I actually came to understand this: https://github.com/pypa/sample-namespace-packages/tree/master/native

Answer 2

Late to the party, but never hurts to help fellow travellers down the namespace path in Python!

#1:

With the __init__.py, which of these should I be using (if any)?:

It depends, There are three ways to do namespace packages as listed here:

1. Use native namespace packages. This type of namespace package is defined in PEP 420 and is available in Python 3.3 and later. This is recommended if packages in your namespace only ever need to support Python 3 and installation via pip.

2. Use pkgutil-style namespace packages. This is recommended for new packages that need to support Python 2 and 3 and installation via both pip and python setup.py install.

3. Use pkg_resources-style namespace packages. This method is recommended if you need compatibility with packages already using this method or if your package needs to be zip-safe.

If you are using #2 (pkgutil-style) or #3 (pkg_resources-style), then you will have to use the corresponding style for __init__.py files. If you use native namespaces then no __init__.py in the namespace directory.

#2:

With setup.py, do I still need to add the namespace_modules parameter, and if so, would I use namespace_modules=['org.common'], or namespace_modules=['org', 'common']?

If your choice of namespace package is not native style, then yes, you will need namespace_packages in your setup().

#3:

Could I forgo all of the above by just implementing this differently somehow? Perhaps something simpler or more "pythonic"?

Since you ended up down to a comple topic in python, it seems you know what you are doing, what you want and identified that creating a Python Namespace package is the way to do it. This would be considered a pythonic way to solve a problem.

---

Adding to your questions, here are a few things I discovered:

I read PEP420, the Python Packaging guide and spent a lot of time understanding the namespace packages, and I generally understood how it worked. I read through a couple of answers here, here, here, and this answer on StackOverflow as well. The example here and on the Git link shared by Rob.

My problem was however after I created my package. As all the instructions and sample code explicitly listed the package in the setuptools.setup(package=[]) function, my code failed. My sub-packages/directories were not included. Digging deeper, I found out that setuptools has a find_namespace_package() function that helps in adding sub-packages too

EDIT:

Link to find_namespace_packages() (setuptools version greater than 40.1.0): https://setuptools.readthedocs.io/en/latest/setuptools.html#find-namespace-packages

EDIT (08/09/2019):

To complete the answer, let me also restructure with an example.

The following solution is assuming Python 3.3+ which has support for implicit namespace packages

Since you are looking for a solution for Python version 3.5 or later, let's take the code samples provided and elaborate further.

Let's assume the following:

Namespace/Python package name : org

Distribution packages: org_client, org_common

Python: 3.3+

setuptools: 40.1.0

For you to do the following

from org.client.client1 import mod1
from org.common import config

And keeping your top level directories the same, viz. org_client_client1_mod1 and org_common_config, you can change your structure to the following

Repository 1:

org_client_client1_mod1/
  setup.py
  org/
    client/
      client1/
        __init__.py
        submod1/
          __init__.py
        mod1/
          __init__.py
          somefile.py
        file1.py

Updated setup.py

from setuptools import find_namespace_packages, setup
setup(
    name="org_client",
    ...
    packages=find_namespace_packages(), # Follows similar lookup as find_packages()
    ...
)

Repository 2:

org_common_config/
  setup.py
  org/
    common/
      __init__.py
      config/
        __init__.py
        someotherfile.py

Updated setup.py:

from setuptools import find_namespace_packages, setup
setup(
    name="org_common",
    ...
    packages=find_namespace_packages(), # Follows similar lookup as find_packages()
    ...
)

To install (using pip):

(venv) $ pip3 install org_common_config/
(venv) $ pip3 install org_client_client1_mod1/

Updated pip list will show the following:

(venv) $ pip3 list
...
org_client
org_common
...

But they won't be importable, for importing you will have to follow org.client and org.common notation.

To understand why, you can browse here (assuming inside venv):

(venv) $ cd venv/lib/python3.5/site-packages/
(venv) $ ls -l | grep org

You'll see that there's no org_client or org_common directories, they are interpreted as a namespace package.

(venv) $ cd venv/lib/python3.5/site-packages/org/
(venv) $ ls -l
client/
common/
...