Get child Node of another Node, given node name

Question

I have an XML like this:

  
    1
    Declaration of Human Rights

        

Answer 1

Check if the Node is a Dom Element, cast, and call getElementsByTagName()

Node doc = docs.item(i);
if(doc instanceof Element) {
    Element docElement = (Element)doc;
    ...
    cell = doc.getElementsByTagName("aoo").item(0);
}

Answer 2

If the Node is not just any node, but actually an Element (it could also be e.g. an attribute or a text node), you can cast it to Element and use getElementsByTagName.

Answer 3

You should read it recursively, some time ago I had the same question and solve with this code:

public void proccessMenuNodeList(NodeList nl, JMenuBar menubar) {
    for (int i = 0; i < nl.getLength(); i++) {
        proccessMenuNode(nl.item(i), menubar);
    }
}

public void proccessMenuNode(Node n, Container parent) {
    if(!n.getNodeName().equals("menu"))
        return;
    Element element = (Element) n;
    String type = element.getAttribute("type");
    String name = element.getAttribute("name");
    if (type.equals("menu")) {
        NodeList nl = element.getChildNodes();
        JMenu menu = new JMenu(name);

        for (int i = 0; i < nl.getLength(); i++)
            proccessMenuNode(nl.item(i), menu);

        parent.add(menu);
    } else if (type.equals("item")) {
        JMenuItem item = new JMenuItem(name);
        parent.add(item);
    }
}

Probably you can adapt it for your case.

Answer 4

//xn=list of parent nodes......                
foreach (XmlNode xn in xnList)
{                                           
    foreach (XmlNode child in xn.ChildNodes) 
    {
        if (child.Name.Equals("name")) 
        {
            name = child.InnerText; 
        }
        if (child.Name.Equals("age"))
        {
            age = child.InnerText; 
        }
    }
}