How to Compare two Arrays are Equal using Javascript? [duplicate]

Answer 1

If you comparing 2 arrays but values not in same index, then try this

var array1=[1,2,3,4]
var array2=[1,4,3,2]
var is_equal = array1.length==array2.length && array1.every(function(v,i) { return ($.inArray(v,array2) != -1)})
console.log(is_equal)

Answer 2

A more modern version:

function arraysEqual(a, b) {
  a = Array.isArray(a) ? a : [];
  b = Array.isArray(b) ? b : [];
  return a.length === b.length && a.every((el, ix) => el === b[ix]);
}

Coercing non-array arguments to empty arrays stops a.every() from exploding.

If you just want to see if the arrays have the same set of elements then you can use Array.includes():

function arraysContainSame(a, b) {
  a = Array.isArray(a) ? a : [];
  b = Array.isArray(b) ? b : [];
  return a.length === b.length && a.every(el => b.includes(el));
}

Answer 3

function isEqual(a) {
if (arrayData.length > 0) {
    for (var i in arrayData) {
        if (JSON.stringify(arrayData[i]) === JSON.stringify(a)) {
            alert("Ya existe un registro con esta informacion");
            return false;
        }
    }
}
}

Check this example

Answer 4

You could try this simple approach

var array1 = [4,8,9,10];
var array2 = [4,8,9,10];

console.log(array1.join('|'));
console.log(array2.join('|'));

if (array1.join('|') === array2.join('|')) {
	console.log('The arrays are equal.');
} else {
	console.log('The arrays are NOT equal.');
}

array1 = [[1,2],[3,4],[5,6],[7,8]];
array2 = [[1,2],[3,4],[5,6],[7,8]];

console.log(array1.join('|'));
console.log(array2.join('|'));

if (array1.join('|') === array2.join('|')) {
	console.log('The arrays are equal.');
} else {
	console.log('The arrays are NOT equal.');
}

If the position of the values are not important you could sort the arrays first.

if (array1.sort().join('|') === array2.sort().join('|')) {
    console.log('The arrays are equal.');
} else {
    console.log('The arrays are NOT equal.');
}