Bash, grep between two lines with specified string

Question

Example:

a43
test1
abc
cvb
bnm
test2
kfo

I need all lines between test1 and test2. Normal grep does not work in this case. Do you have any

Answer 1

The following script wraps up this process. More details in this similar StackOverflow post

get_text.sh

function show_help()
{
  HELP=$(doMain $0 HELP)
  echo "$HELP"
  exit;
}

function doMain()
{
  if [ "$1" == "help" ]
  then
    show_help
  fi
  if [ -z "$1" ]
  then
    show_help
  fi
  if [ -z "$2" ]
  then
    show_help
  fi

  FILENAME=$1
  if [ ! -f $FILENAME ]; then
      echo "File not found: $FILENAME"
      exit;
  fi

  if [ -z "$3" ]
  then
    START_TAG=$2_START
    END_TAG=$2_END
  else
    START_TAG=$2
    END_TAG=$3
  fi

  CMD="cat $FILENAME | awk '/$START_TAG/{f=1;next} /$END_TAG/{f=0} f'"
  eval $CMD
}

function help_txt()
{
HELP_START
  get_text.sh: extracts lines in a file between two tags

  usage: FILENAME {TAG_PREFIX|START_TAG} {END_TAG}

  examples:
    get_text.sh 1.txt AA     => extracts lines in file 1.txt between AA_START and AA_END
    get_text.sh 1.txt AA BB  => extracts lines in file 1.txt between AA and BB
HELP_END
}

doMain $*

Answer 2

The answer by PratPor above:

cat test.txt | grep -A10 test1 | grep -B10 test2

is cool.. but if you don't know the file length:

cat test.txt | grep -A1000 test1 | grep -B1000 test2

Not deterministic, but not too bad. Anyone have better (more deterministic)?