Example:
a43
test1
abc
cvb
bnm
test2
kfo
I need all lines between test1 and test2. Normal grep does not work in this case. Do you have any
If you can only use grep:
grep -A100000 test1 file.txt | grep -B100000 test2 > new.txt
grep -A
and then a number gets the lines after the matching string, and grep -B
gets the lines before the matching string. The number, 100000 in this case, has to be large enough to include all lines before and after.
If you don't want to include test1 and test2, then you can remove them afterwards by grep -v
, which prints everything except the matching line(s):
egrep -v "test1|test2" new.txt > newer.txt
or everything in one line:
grep -A100000 test1 file.txt | grep -B100000 test2 | egrep -v "test1|test2" > new.txt
Print from
test1
totest2
(Trigger lines included)
awk '/test1/{f=1} /test2/{f=0;print} f'
awk '/test1/{f=1} f; /test2/{f=0}'
awk '/test1/,/test2/'
test1
abc
cvb
bnm
test2
Prints data between
test1
totest2
(Trigger lines excluded)
awk '/test1/{f=1;next} /test2/{f=0} f'
awk '/test2/{f=0} f; /test1/{f=1}'
abc
cvb
bnm
You can do something like this too. Lets say you this file test.txt
with content:
a43
test1
abc
cvb
bnm
test2
kfo
You can do
cat test.txt | grep -A10 test1 | grep -B10 test2
where -A<n>
is to get you n
lines after your match in the file and -B<n>
is to give you n
lines before the match. You just have to make sure that n > number of expected lines between test1 and test2
. Or you can give it large enough to reach EOF.
Result:
test1
abc
cvb
bnm
test2
You could use sed
:
sed -n '/test1/,/test2/p' filename
In order to exclude the lines containing test1
and test2
, say:
sed -n '/test1/,/test2/{/test1/b;/test2/b;p}' filename
To make it more deterministic and not having to worry about size of file, use the wc -l and cut the output.
grep -Awc -l test.txt|cut -d" " -f1
test1 test.txt | grep -Bwc -l test.txt|cut -d" " -f1
test2
To make it easier to read, assign it to a variable first.
fsize=wc -l test.txt|cut -d" " -f1
; grep -A$fsize test1 test.txt | grep -B$fsize test2
Yep, normal grep won't do this. But grep with -P
parameter will do this job.
$ grep -ozP '(?s)test1\n\K.*?(?=\ntest2)' file
abc
cvb
bnm
\K
discards the previously matched characters from printing at the final and the positive lookahead (?=\ntest2)
asserts that the match must be followed by a \n
newline character and then test2
string.