Sort array of objects in specific order

Question

I have an array of objects returning from an API call which I need to sort into a specific format.

I\'m trying to organise the destination_country_id alphab

Answer 1

If your provided array is called list, you can sort it as you want using the following call:

list.sort(function (item1, item2) {
    if (item1.destination_country_name < item2.destination_country_name) {
        return -1;
    }
    return 1;
});

Answer 2

I think the most efficient way to sort your array is to first find where "Everywhere Else", the "UK", "Ireland", and the "US" are in your array, remove them, and then sort the rest of the array. This is simpler than it sounds

fiddle

var data = [
    {"destination_country_name": "Everywhere Else"},
    {"destination_country_name": "United Kingdom"},
    {"destination_country_name": "United States"},
    {"destination_country_name": "Ireland"},
    {"destination_country_name": "France"},
    {"destination_country_name": "Spain"}     ];
//removed the other elements just to make the example cleaner
var keep = ["Everywhere Else", "Ireland", "United Kingdom", "United States"];
//keep is the elements you want in the front; order them exactly at you want them ordered
var top = [];
//this is our holder array to hold the objects for the strings in keep

for (var i = 0; i < keep.length; i++) {
    var index = function () {
        for (var j = 0; j < data.length; j++){    //loop through data
            if (data[j].destination_country_name == keep[i])
                return data[j];    //return the object if it's name matches the one in keep
        }
    }
    if (index > -1){        //if the object is in the array (index != -1)
        top.push(data[index]);    //push the object to our holder array
        data.splice(index, 1);    //splice the object out of the original array
    }
}
//after this loop, those other objects will have been removed
//sort the rest of that array of objects
data.sort(function (a, b) {    //use a callback function to specify which parts of
                               //the object need to be sorted
    //basic sorting/compare algorithm (-1, 0, or 1)
    if (a.destination_country_name > b.destination_country_name)
        return 1;        //if greater
    if (a.destination_country_name < b.destination_country_name)
        return -1;        //if lesser
    return 0;    //otherwise
})

var sorted = top.concat(data), //combine data to the holder array and assign to sorted
    extra = sorted.shift();    //grab the first element ("Everywhere Else") and remove it
    sorted.push(extra);        //add that element to the end of the array
console.log(sorted);

Alternatively, if you know those four places (EE, UK, US, and Ireland) will always be the first 4 elements in your array, you can do the following:

var data = [
    {"destination_country_name": "Everywhere Else"},
    {"destination_country_name": "United Kingdom"},
    {"destination_country_name": "United States"},
    {"destination_country_name": "Ireland"},
    {"destination_country_name": "France"},
    {"destination_country_name": "Spain"}     ];

var top = data.slice(0,4);
data.sort(function (a, b) {
    if (a.destination_country_name > b.destination_country_name)
        return 1;
    if (a.destination_country_name < b.destination_country_name)
        return -1;
    return 0;
})

var sorted = top.concat(data),
        extra = sorted.shift();
        sorted = sorted.push(extra);    //put "Everywhere Else" at the end of the array

Note how this is much more efficient (and much simpler!) because you don't need to locate those four elements.

Answer 3

You can give every object a 'sort-order' property. Specify the known first 3 and the last, and give all the others the same value, greater than the first three and less than the last. Then sort the array- first by sort-order, and then alphabetically;

var arr= [{ "destination_country_id": null, "primary_cost": "9.50", "region_id": null, "destination_country_name": "Everywhere Else", },{ "destination_country_id": 105, "primary_cost": "8.00", "region_id": null, "destination_country_name": "United Kingdom", },{ "destination_country_id": 209, "primary_cost": "9.50", "region_id": null, "destination_country_name": "United States", },{ "destination_country_id": 123, "primary_cost": "5.00", "region_id": null, "destination_country_name": "Ireland", },{ "destination_country_id": 185, "primary_cost": "5.00", "region_id": null, "destination_country_name": "France", },{ "destination_country_id": 145, "primary_cost": "5.00", "region_id": null, "destination_country_name": "Spain", }]

var s= "destination_country_name",
order= ["Ireland", "United Kingdom", 
"United States", "Everywhere Else"];

arr.forEach(function(itm){
    var i= order.indexOf(itm[s]);
    if(i!= -1) itm.sort_order= i== 3? 1e50: i;
    else itm.sort_order= 10;
});

arr.sort(function(a, b){
    var d= a.sort_order- b.sort_order;
    if(d===0){
        if(a[s]=== b[s]) return 0;
        return a[s]>b[s]? 1: -1;
    }
    return d;
});
JSON.stringify(arr)
/*  returned value: (String)[{
        "destination_country_id": 123, "primary_cost": "5.00", "region_id": null, 
        "destination_country_name": "Ireland", "sort_order": 0
    },{
        "destination_country_id": 105, "primary_cost": "8.00", "region_id": null, 
        "destination_country_name": "United Kingdom", "sort_order": 1
    },{
        "destination_country_id": 209, "primary_cost": "9.50", "region_id": null, 
        "destination_country_name": "United States", "sort_order": 2
    },{
        "destination_country_id": 185, "primary_cost": "5.00", "region_id": null, 
        "destination_country_name": "France", "sort_order": 10
    },{
        "destination_country_id": 145, "primary_cost": "5.00", "region_id": null, 
        "destination_country_name": "Spain", "sort_order": 10
    },{
        "destination_country_id": null, "primary_cost": "9.50", "region_id": null, 
        "destination_country_name": "Everywhere Else", "sort_order": 1e+50
    }
]
*/

Answer 4

Possibly not the most efficient method but it is ES3, doesn't require any libraries, and is fairly easy to understand. Also assuming you wanted to sort alphabetically on destination_country_name

Javascript

// where x is your array of objects
x.sort(function (a, b) {
    // sorts everything alphabetically
    return a.destination_country_name.localeCompare(b.destination_country_name);
}).sort(function (a, b) {
    // moves only this to country to top
    return +(!b.destination_country_name.localeCompare('United States'));
}).sort(function (a, b) {
    // moves only this to country to top
    return +(!b.destination_country_name.localeCompare('United Kingdom'));
}).sort(function (a, b) {
    // moves only this to country to top
    return +(!b.destination_country_name.localeCompare('Ireland'));
}).sort(function (a, b) {
    // moves only this to country to bottom
    return +(!a.destination_country_name.localeCompare('Everywhere Else'));
});

console.log(JSON.stringify(x, ['destination_country_name']));

Output

[{"destination_country_name":"Ireland"},
 {"destination_country_name":"United Kingdom"},
 {"destination_country_name":"United States"},
 {"destination_country_name":"France"},
 {"destination_country_name":"Spain"},
 {"destination_country_name":"Everywhere Else"}]

On jsFiddle

We could even go a step further and use the above example to make a reusable function, like.

Javascript

function sorter(array, funcs, orders) {
    funcs = funcs || {};
    orders = orders || {};
    array.sort(funcs.general);
    if (Array.isArray(orders.top)) {
        orders.top.slice().reverse().forEach(function(value) {
            array.sort(funcs.top.bind(value));
        });
    }

    if (Array.isArray(orders.bottom)) {
        orders.bottom.forEach(function(value) {
            array.sort(funcs.bottom.bind(value));
        });
    }

    return array;
}

sorter(x, {
    general: function (a, b) {
        return a.destination_country_name.localeCompare(b.destination_country_name);
    },
    top: function (a, b) {
        return +(!b.destination_country_name.localeCompare(this));
    },
    bottom: function (a, b) {
        return +(!a.destination_country_name.localeCompare(this));
    }
}, {
    top: ['Ireland', 'United Kingdom', 'United States'],
    bottom: ['Everywhere Else']
});

On jsFiddle

And now you can easily sort on different attributes by parsing in different compare functions, and define values that should be at the top or bottom.

I used ECMA5 methods but you could just as easily make it with ECMA3.

Answer 5

you can use underscore sortBy method:

a=[{obj:'first3'},{obj:'first2'},{obj:'first1'},{obj:'z'},{obj:'m'},{obj:'c'},{obj:'end3'},{obj:'end2'},{obj:'end1'}]
a=_.sortBy(a,function (t,i){if (i<=2) return String.fromCharCode(0);if(i>=a.length-3) return String.fromCharCode(255);return t.obj })

console.log(JSON.stringify(a))

[{"obj":"first3"},{"obj":"first2"},{"obj":"first1"},{"obj":"c"},{"obj":"m"},{"obj":"z"},{"obj":"end3"},{"obj":"end2"},{"obj":"end1"}]

http://jsfiddle.net/43Q8h/