When I pass a row of a data frame to a function using apply, I lose the class information of the elements of that row. They all turn into \'character\'. The following is a sim
apply
only really works on matrices (which have the same type for all elements). When you run it on a data.frame
, it simply calls as.matrix
first.
The easiest way around this is to work on the numeric columns only:
# skips the first column
a <- apply(df[, -1, drop=FALSE],1, dfunc)
# Or in two steps:
m <- as.matrix(df[, -1, drop=FALSE])
a <- apply(m,1, dfunc)
The drop=FALSE
is needed to avoid getting a single column vector.
-1
means all-but-the first column, you could instead explicitly specify the columns you want, for example df[, c('foo', 'bar')]
UPDATE
If you want your function to access one full data.frame row at a time, there are (at least) two options:
# "loop" over the index and extract a row at a time
sapply(seq_len(nrow(df)), function(i) dfunc(df[i,]))
# Use split to produce a list where each element is a row
sapply(split(df, seq_len(nrow(df))), dfunc)
The first option is probably better for large data frames since it doesn't have to create a huge list structure upfront.