I have this problem, I have two divs:
<
Since you know how many pixels are occupied by the previous content, you can use the calc()
function:
height: calc(100% - 50px);
<div>
<div id="header">header</div>
<div id="content">content</div>
<div id="footer">footer</div>
</div>
#header {
height: 200px;
}
#content {
height: 100%;
margin-bottom: -200px;
padding-bottom: 200px;
margin-top: -200px;
padding-top: 200px;
}
#footer {
height: 200px;
}
With CSS tables, you could wrap a div around the two you have there and use this css/html structure:
<style type="text/css">
.container { display:table; width:100%; height:100%; }
#div1 { display:table-row; height:50px; background-color:red; }
#div2 { display:table-row; background-color:blue; }
</style>
<div class="container">
<div id="div1"></div>
<div id="div2"></div>
</div>
Depends on what browsers support these display types, however. I don't think IE8 and below do. EDIT: Scratch that-- IE8 does support CSS tables.
I faced the same challenge myself and found these 2 answers using flex
properties.
CSS
.container {
display: flex;
flex-direction: column;
}
.dynamic-element{
flex: 1;
}
You can use this http://jsfiddle.net/Victornpb/S8g4E/783/
#container {
display: table;
width: 400px;
height: 400px;
}
#container > div{
display: table-row;
height: 0;
}
#container > div.fill{
height: auto;
}
Just apply the class .fill
to any of the children to make then occupy the remaining height.
<div id="container">
<div>
Lorem ipsum
</div>
<div>
Lorem ipsum
</div>
<div class="fill"> <!-- this will fill the remaining height-->
Lorem ipsum
</div>
</div>
It works with how many children you want, no additional markup is required.