Is there a way to save all of the print output to a txt file in python? Lets say I have the these two lines in my code and I want to save the print output to a file named
You can redirect stdout into a file "output.txt":
import sys
sys.stdout = open('output.txt','wt')
print ("Hello stackoverflow!")
print ("I have a question.")
Another Variation can be... Be sure to close the file afterwards
import sys
file = open('output.txt', 'a')
sys.stdout = file
print("Hello stackoverflow!")
print("I have a question.")
file.close()
Another method without having to update your Python code at all, would be to redirect via the console.
Basically, have your Python script print()
as usual, then call the script from the command line and use command line redirection. Like this:
$ python ./myscript.py > output.txt
Your output.txt
file will now contain all output from your Python script.
Edit:
To address the comment; for Windows, change the forward-slash to a backslash.
(i.e. .\myscript.py
)
Use the logging module
def init_logging():
rootLogger = logging.getLogger('my_logger')
LOG_DIR = os.getcwd() + '/' + 'logs'
if not os.path.exists(LOG_DIR):
os.makedirs(LOG_DIR)
fileHandler = logging.FileHandler("{0}/{1}.log".format(LOG_DIR, "g2"))
rootLogger.addHandler(fileHandler)
rootLogger.setLevel(logging.DEBUG)
consoleHandler = logging.StreamHandler()
rootLogger.addHandler(consoleHandler)
return rootLogger
Get the logger:
logger = init_logging()
And start logging/output(ing):
logger.debug('Hi! :)')
Suppose my input file is "input.txt" and output file is "output.txt".
Let's consider the input file has details to read:
5
1 2 3 4 5
Code:
import sys
sys.stdin = open("input", "r")
sys.stdout = open("output", "w")
print("Reading from input File : ")
n = int(input())
print("Value of n is :", n)
arr = list(map(int, input().split()))
print(arr)
So this will read from input file and output will be displayed in output file.
For more details please see https://www.geeksforgeeks.org/inputoutput-external-file-cc-java-python-competitive-programming/
Give print
a file
keyword argument, where the value of the argument is a file stream. We can create a file stream using the open
function:
print("Hello stackoverflow!", file=open("output.txt", "a"))
print("I have a question.", file=open("output.txt", "a"))
From the Python documentation about print:
The
file
argument must be an object with awrite(string)
method; if it is not present orNone
,sys.stdout
will be used.
And the documentation for open:
Open
file
and return a corresponding file object. If the file cannot be opened, anOSError
is raised.
The " a "
as the second argument of open
means "append" - in other words, the existing contents of the file won't be overwritten. If you want the file to be overwritten instead, use "w"
.
Opening a file with open
many times isn't ideal for performance, however. You should ideally open it once and name it, then pass that variable to print
's file
option. You must remember to close the file afterward!
f = open("output.txt", "a")
print("Hello stackoverflow!", file=f)
print("I have a question.", file=f)
f.close()
There's also a syntactic shortcut for this, which is the with
block. This will close your file at the end of the block for you:
with open("output.txt", "a") as f:
print("Hello StackOverflow!", file=f)
print("I have a question.", file=f)