My app has ability to select photo from library. Exactly I want file path from this selection.
This is the code to create intent for selecting photo:
This is most certainly a workaround, but you could extract the real content URI which has apparently become embedded for some reason: content%3A%2F%2Fmedia%2Fexternal%2Fimages%2Fmedia%2F75209
I was able to create a new URI with authority=media and path=external/images/media/xxx
, and content resolver returned a real URL.
Example code:
String unusablePath = contentUri.getPath();
int startIndex = unusablePath.indexOf("external/");
int endIndex = unusablePath.indexOf("/ACTUAL");
String embeddedPath = unusablePath.substring(startIndex, endIndex);
Uri.Builder builder = contentUri.buildUpon();
builder.path(embeddedPath);
builder.authority("media");
Uri newUri = builder.build();
I know this question is bit old, still I did the following to get the image from gallery and use it. Below is the extension function for the same.
fun Uri.toBitmap(context: Context?): Bitmap {
return MediaStore.Images.Media.getBitmap(context?.contentResolver, this)
}
It takes context as parameter to get contentResolver and Uri received from onActivityResult(requestCode: Int, resultCode: Int, intent: Intent?).
To use, just do the following:
intent?.data.toBitmap(context)
where intent?.data
is the Uri received from onActivityResult().
Below code is working for me to get content URI on latest Google Photos as well. What i have tried is writing to temp file and return temp image URI, if it has authority in content URI.
You can try same:
private static String getImageUrlWithAuthority(Context context, Uri uri)
{
InputStream is = null;
if (uri.getAuthority() != null)
{
try
{
is = context.getContentResolver().openInputStream(uri);
Bitmap bmp = BitmapFactory.decodeStream(is);
return writeToTempImageAndGetPathUri(context, bmp).toString();
}
catch (FileNotFoundException e)
{
e.printStackTrace();
}
finally
{
try
{
if (is != null)
{
is.close();
}
}
catch (IOException e)
{
e.printStackTrace();
}
}
}
return null;
}
private static Uri writeToTempImageAndGetPathUri(Context inContext, Bitmap inImage)
{
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
String path = MediaStore.Images.Media.insertImage(inContext.getContentResolver(), inImage, "Title", null);
return Uri.parse(path);
}