Django - How to make a variable available to all templates?

后端 未结 2 1464
余生分开走
余生分开走 2020-11-27 12:22

I would like to know how to pass a variable to all my templates, without repeating the same code on every method in my views.py file?

In the example below I would l

相关标签:
2条回答
  • 2020-11-27 12:56

    What you want is a context processor, and it's very easy to create one. Assuming you have an app named custom_app, follow the next steps:

    • Add custom_app to INSTALLED_APPS in settings.py (you've done it already, right?);
    • Create a context_processors.py into custom_app folder;
    • Add the following code to that new file:

      def categories_processor(request):
       categories = Category.objects.all()            
       return {'categories': categories}
      
    • Add context_processors.py to TEMPLATE_CONTEXT_PROCESSORS in settings.py

      TEMPLATE_CONTEXT_PROCESSORS += ("custom_app.context_processors.categories_processor", )
      

    And now you can use {{categories}} in all the templates :D

    As of Django 1.8

    To add a TEMPLATE_CONTEXT_PROCESSORS, in the settings you must add the next code:

    TEMPLATES[0]['OPTIONS']['context_processors'].append("custom_app.context_processors.categories_processor")
    

    Or include that string directly in the OPTIONS.context_processors key in your TEMPLATES setting.

    0 讨论(0)
  • 2020-11-27 13:16

    As seen in this example, post Django 1.3 you can simply use render instead of render_to_response which doesn't require you to explicitly pass the context processor.

    def another_view_method(request):
        categories = Category.objects.all()
        return render(
            'eg/front_page.html',
            {'is_logged_in': is_logged_in(request), 'categories':categories}
        )
    
    0 讨论(0)
提交回复
热议问题