POST a form array without successful

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误落风尘
误落风尘 2020-11-21 05:07

I\'m developing an ASP.NET MVC 5 web with C# and .NET Framework 4.5.1.

I have this form in a cshtml file:

@model MyProduct.         


        
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  • 2020-11-21 05:31

    using(Html.BeginForm())
    {
      // code here 
    
    }

    While to Post form Data all tags must be included form tag.

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  • 2020-11-21 05:35

    Following the principle of DRY, you can create one EditorTemplate for that purpose. Steps:

    1- In Views > Shared > Create new folder named (EditorTemplates)

    2- Create a view inside your newly created EditorTemplates folder , the view's model should be BatchProductViewModel according to the OP example. Place your code inside the Editor view. No loop or index is required.

    An EditorTemplate will act similar to a PartialView for every child entity but in a more generic way.

    3- In your parent entity's view, call your Editor : @Html.EditorFor(m => m.BatchProducts)

    Not only this provides a more organized views, but also let's you re-use the same editor in other views as well.

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  • 2020-11-21 05:41

    You need to generate the controls for the collection in a for loop so they are correctly named with indexers (note that property BatchProducts needs to be IList<BatchProductViewModel>

    @using (Html.BeginForm("Save", "ConnectBatchProduct", FormMethod.Post))
    {
      ....
      <table>
        ....
        @for(int i = 0; i < Model.BatchProducts.Count; i++)
        {
          <tr>
            <td>@Html.TextBoxFor(m => m.BatchProducts[i].Quantity)</td>
            <td>@Html.TextBoxFor(m => m.BatchProducts[i].BatchName)</td>
            <td>
              // add the following to allow for dynamically deleting items in the view
              <input type="hidden" name="BatchProducts.Index" value="@i" />
              <a class="deleteRow"></a>
            </td>
          </tr>
        }
        ....
      </table>
      ....
    }
    

    Then the POST method needs to be

    public ActionResult Save(ConnectBatchProductViewModel model)
    {
      ....
    }
    

    Edit

    Note: Further to your edit, if you want to dynamically add and remove BatchProductViewModel items in he view, you will need to use the BeginCollectionItem helper or a html template as discussed in this answer

    The template to dynamically add new items would be

    <div id="NewBatchProduct" style="display:none">
      <tr>
        <td><input type="text" name="BatchProducts[#].Quantity" value /></td>
        <td><input type="text" name="BatchProducts[#].BatchName" value /></td>
        <td>
          <input type="hidden" name="BatchProducts.Index" value ="%"/>
          <a class="deleteRow"></a>
        </td>
      </tr>
    </div>
    

    Note the dummy indexers and the non-matching value for the hidden input prevents this template posting back.

    Then the script to add a new BatchProducts would be

    $("#addrow").click(function() {
      var index = (new Date()).getTime(); // unique indexer
      var clone = $('#NewBatchProduct').clone(); // clone the BatchProducts item
      // Update the index of the clone
      clone.html($(clone).html().replace(/\[#\]/g, '[' + index + ']'));
      clone.html($(clone).html().replace(/"%"/g, '"' + index  + '"'));
      $("table.order-list").append(clone.html());
    });
    
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  • 2020-11-21 05:41

    In your Post Methode you receive "MyProduct.Web.API.Models.ConnectBatchProductViewModel" as Parameter.
    Use the existing model for the Post methode.

    Why do you want a IEnumerable from your model? there is only one available including the id in the model.

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  • 2020-11-21 05:49

    you can visit this article for complete source code with a video tutorial.

    you have to create an action first, from where we can pass the list of object

    [HttpGet]
    public ActionResult Index()
    {
        List<Contact> model = new List<Contact>();
        using (MyDatabaseEntities dc = new MyDatabaseEntities())
        {
            model = dc.Contacts.ToList();
        }
        return View(model);
    }
    

    then we need to create a view for that action

    @model List<UpdateMultiRecord.Contact>
    @{
        ViewBag.Title = "Update multiple row at once Using MVC 4 and EF ";
    }
    @using (@Html.BeginForm("Index","Home", FormMethod.Post))
    {
        <table>
                <tr>
                    <th></th>               
                    <th>Contact Person</th>
                    <th>Contact No</th>
                    <th>Email ID</th>
                </tr>
            @for (int i = 0; i < Model.Count; i++)
            {
                <tr>               
                    <td> @Html.HiddenFor(model => model[i].ContactID)</td>
                    <td>@Html.EditorFor(model => model[i].ContactPerson)</td>
                    <td>@Html.EditorFor(model => model[i].Contactno)</td>
                    <td>@Html.EditorFor(model => model[i].EmailID)</td>
                </tr>
            }
        </table>
        <p><input type="submit" value="Save" /></p>
        <p style="color:green; font-size:12px;">
            @ViewBag.Message
        </p>
    }
     @section Scripts{
        @Scripts.Render("~/bundles/jqueryval")
     }
    

    and then we have to write code for save the list of object to the database

    [HttpPost]
    public ActionResult Index(List<Contact> list)
    {  
        if (ModelState.IsValid)
        {
            using (MyDatabaseEntities dc = new MyDatabaseEntities())
            {
                foreach (var i in list)
                {
                    var c = dc.Contacts.Where(a =>a.ContactID.Equals(i.ContactID)).FirstOrDefault();
                    if (c != null)
                    {
                        c.ContactPerson = i.ContactPerson;
                        c.Contactno = i.Contactno;
                        c.EmailID = i.EmailID;
                    }
                }
                dc.SaveChanges();
            }
            ViewBag.Message = "Successfully Updated.";
            return View(list);
        }
        else
        {
            ViewBag.Message = "Failed ! Please try again.";
            return View(list);
        }
    }
    
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