How to print time in format: 2009‐08‐10 18:17:54.811

Question

What\'s the best method to print out time in C in the format 2009‐08‐10 
18:17:54.811?

Answer 1

trick:

    int time_len = 0, n;
    struct tm *tm_info;
    struct timeval tv;

    gettimeofday(&tv, NULL);
    tm_info = localtime(&tv.tv_sec);
    time_len+=strftime(log_buff, sizeof log_buff, "%y%m%d %H:%M:%S", tm_info);
    time_len+=snprintf(log_buff+time_len,sizeof log_buff-time_len,".%03ld ",tv.tv_usec/1000);