All the samples for Rijndael algorithm are defining the key from the Rijndael class itself, can\'t we provide the Key of our own. Any hint on this will help me a lot.
Th
The key property of the Rijndael instance takes a byte[] as the key. Make sure you set it to an array with a valid size for the algorithm.
Link to msdn: http://msdn.microsoft.com/en-us/library/system.security.cryptography.symmetricalgorithm.key.aspx
What do you mean by cannot provide the key of our own? Here's an example on how you do it.
public static string Encrypt(string Text, byte[] key, byte[] VectorBytes){
try{
byte[] TextBytes = Encoding.UTF8.GetBytes(Text);
RijndaelManaged rijKey = new RijndaelManaged();
rijKey.Mode = CipherMode.CBC;
ICryptoTransform encryptor = rijKey.CreateEncryptor(key,VectorBytes);
MemoryStream memoryStream = new MemoryStream();
cryptoStream.Write(TextBytes, 0, TextBytes.Length);
cryptoStream.FlushFinalBlock();
byte[] cipherTextBytes = memoryStream.ToArray();
memoryStream.Close();
cryptoStream.Close();
string cipherText = Convert.ToBase64String(cipherTextBytes);
return cipherText;
}
catch (Exception e){
MessageBox.Show("Falsches Passwort "+ e.Message.ToString());
string t = "";
return t;
}
}
You can try something like this, based on the RijndaelManaged Class MSDN article that I also recommend you to read.
var plainText = "This will be encrypted.";
var aesAlg = new RijndaelManaged();
aesAlg.Key = new byte[32] { 118, 123, 23, 17, 161, 152, 35, 68, 126, 213, 16, 115, 68, 217, 58, 108, 56, 218, 5, 78, 28, 128, 113, 208, 61, 56, 10, 87, 187, 162, 233, 38 };
aesAlg.IV = new byte[16] { 33, 241, 14, 16, 103, 18, 14, 248, 4, 54, 18, 5, 60, 76, 16, 191};
ICryptoTransform encryptor = aesAlg.CreateEncryptor(aesAlg.Key, aesAlg.IV);
msEncrypt = new MemoryStream();
using (CryptoStream csEncrypt = new CryptoStream(msEncrypt, encryptor, CryptoStreamMode.Write)) {
using (StreamWriter swEncrypt = new StreamWriter(csEncrypt)) {
swEncrypt.Write(plainText);
}
}
return msEncrypt.ToArray();