Using Python 3.3 in OpenShift's book example

Question

OpenShift recently published a book, \"Getting Started with OpenShift\". It is a good guide for someone just starting out.

In Chapter 3 they show how to modify a templat

Answer 1

As indicated in this question, you can replace the line

execfile(virtualenv, dict(__file__=virtualenv))

by

exec(compile(open(virtualenv, 'rb').read(), virtualenv, 'exec'), dict(__file__=virtualenv))

In my opinion, it would be better to break this up into a few simpler pieces. Also we should use a context handler for the file handling::

with open(virtualenv, 'rb') as exec_file:
    file_contents = exec_file.read()
compiled_code = compile(file_contents, virtualenv, 'exec')
exec_namespace = dict(__file__=virtualenv)
exec(compiled_code, exec_namespace)

Breaking it up in this way will also make debugging easier (actually: possible). I haven't tested this but it should work.

Answer 2

If you are facing issues with virtualenv settings on wsgi.py file in Python3 I have solved just deleting it.

This is my wsgi.py file and it's working

#!/usr/bin/python

from flaskapp import app as application

if __name__ == '__main__':
    from wsgiref.simple_server import make_server
    httpd = make_server('0.0.0.0', 5000, application)
    # Wait for a single request, serve it and quit.
    #httpd.handle_request()
    httpd.serve_forever()