Fastest way to convert file from latin1 to utf-8 in python

Question

I need fastest way to convert files from latin1 to utf-8 in python. The files are large ~ 2G. ( I am moving DB data ). So far I have

import codecs
infile = codec         


        

Answer 1

You could use blocks larger than one line, and do binary I/O -- each might speed thinks up a bit (though on Linux binary I/O won't, as it's identical to text I/O):

 BLOCKSIZE = 1024*1024
 with open(tmpfile, 'rb') as inf:
   with open(tmpfile, 'wb') as ouf:
     while True:
       data = inf.read(BLOCKSIZE)
       if not data: break
       converted = data.decode('latin1').encode('utf-8')
       ouf.write(converted)

The byte-by-byte parsing implied in by-line reading, line-end conversion (not on Linux;-), and codecs.open-style encoding-decoding, should be part of what's slowing you down. This approach is also portable (like yours is), since control-characters such as \n need no translation among these codecs anyway (in any OS).

This only works for input codecs that have no multibyte characters, but `latin1' is one of those (it does not matter whether the output codec has such characters or not).

Try different block sizes to find the sweet spot performance-wise, depending on your disk, filesystem and available RAM.

Edit: changed code per @John's comment, and clarified a conditon as per @gnibbler's.

Answer 2

I would go with iconv and a system call.

Answer 3

If you are desperate to do it in Python (or any other language), at least do the I/O in bigger chunks than lines, and avoid the codecs overhead.

infile = open(tmpfile, 'rb')
outfile = open(tmpfile1, 'wb')
BLOCKSIZE = 65536 # experiment with size
while True:
    block = infile.read(BLOCKSIZE)
    if not block: break
    outfile.write(block.decode('latin1').encode('utf8'))
infile.close()
outfile.close()

Otherwise, go with iconv ... I haven't look under the hood but if it doesn't special-case latin1 input I'd be surprised :-)