How do I use full text search across multiple tables, SQL Server 2005

前端 未结 2 1383
有刺的猬
有刺的猬 2021-02-10 02:05

I have a full text catalog with two tables in it.

tableA has 4 columns (a1, a2, a3, a4) of wich 3 are indexed in the catalog, a2,a3,a4. a1 is the primary key.

t

相关标签:
2条回答
  • 2021-02-10 02:31

    Your query only returns records, if both A and related B contains the search text.

    You do not state what does not work, though.

    Why not LEFT OUTER JOIN the fulltext searches, and replace:

    SELECT *, (ISNULL(ftTableA.[RANK], 0) + ISNULL(ftTableB.[RANK], 0)) AS total_rank 
    

    and

    WHERE ftTableA.Key IS NOT NULL OR ftTableB.Key IS NOT NULL
    
    0 讨论(0)
  • 2021-02-10 02:40

    I'm not positive that I understood what you were trying to do. I interpreted your question as you want to return all items in Table A that matched the search term. Furthermore you wanted to sum the rank from the item in TableA plus the matching items in TableB.

    The best way I can think to do this is to use a table variable with 3 queries.

    DECLARE @Results Table (a1 Int UNIQUE, Rank Int)
    
    --Insert into @Results all matching items from TableA
    INSERT INTO @Results
    (a1, Rank)
    ( SELECT TableA.a1, FT.Rank
    FROM TableA INNER JOIN FreeTextTable(TableA, *, 'search term') FT
    ON TableA.A1 = FT.[Key]
    )
    
    --Update all of the ranks in @Results with a sum of current value plus the sum of
    --all sub items (in TableB)
    UPDATE @Results
    SET Rank = RS.Rank + FT.Rank
    FROM @Results RS INNER JOIN TableB
    ON RS.A1 = TableB.b2
    INNER JOIN FreeTextTable(TableB, *, 'search term') FT
    ON TableB.b1 = FT.[Key]
    
    --Now insert into @Results any items that has a match in TableB but not in TableA
    --This query may/may not be desired based on your business rules.
    INSERT INTO @Results
    (SkillKeyId, Rank)
    ( SELECT TableB.b2, Sum(FT.Rank)
    FROM TableB INNER JOIN FreeTextTable(TableB, *, 'search term') FT
    ON TableB.b1 = FT.[key]
    LEFT JOIN @Results RS
    ON RS.a1 = TableB.b2
    WHERE RS.a1 IS NULL
    GROUP BY TableB.b2
    )
    
    --All that's left is to return the results
    SELECT TableA.*, RS.Rank AS Total_Rank
    FROM TableA INNER JOIN @Results RS
    ON TableA.a1 = RS.a1
    ORDER BY RS.Rank DESC
    
    

    This isn't as elegant as using one query, but it should be easy to follow and allows you to decide whether or not to include records in the 3rd query.

    0 讨论(0)
提交回复
热议问题