I am adding a number of observers in my viewController
-- applicationWillResignActive
, applicationDidEnterBackground
, and many others. I w
Yes
NotificationCenter.default.removeObserver(self)
this line is sufficient to remove the vc observation as long as all are added with
NotificationCenter.default.addObserver
So I'm working with this in an app right now and the answer might not be as straightforward.
In the documentation, it does state that for iOS 9 and above you are no longer required to explicitly remove the observer in the deinit/dealloc methods for objects. https://developer.apple.com/documentation/foundation/notificationcenter/1413994-removeobserver
However, it appears that this is only true for selector based notification observers. I'll be referencing this blog post: https://oleb.net/blog/2018/01/notificationcenter-removeobserver/.
If you are using block based observers you must still manually remove the observers.
addObserver(forName:object:queue:using:)
The best general way to do this is to capture the tokens in an array, append them when you add the observer and use them for removal when you deinit/dealloc or otherwise need to remove observer behavior for your object.
in your VC/object properties create an array to store observer 'tokens'
var notifObservers = [NSObjectProtocol]()
Register for a block based notification by capturing the function return object and storing it as a token
let observer = NotificationCenter.default.addObserver(forName: , object: , queue:) { [weak self] notification in
// do a thing here
}
notifObservers.append(observer)
Removal
for observer in notifObservers {
NotificationCenter.default.removeObserver(observer)
}
notifObservers.removeAll()
@Sh_Khan is right:
NotificationCenter.default.removeObserver(self)
You can get even further, as mentioned in the Apple Documentation:
If your app targets iOS 9.0 and later or macOS 10.11 and later, you don't need to unregister an observer in its dealloc method.