MediaElement.play() from within ViewModel

Question

I\'m struggling with the following issue:

I am building a WP8 application using the MVVM patern. I have a media element on my view.xaml and the logic to control this med

Answer 1

The answer of asitis is great.And I show you my detail code:(use caliburn.micro so don't need to bind name)

View

    <Grid>
         <ContentControl Content="{Binding MediaElementObject}"/>
    </Grid>

    <StackPanel Orientation="Horizontal">
         <Button x:Name="ButtonPlay" Content="Play" Width="220px" Margin="20,5"/>
         <Button x:Name="ButtonStop" Content="Stop" Width="220px" Margin="20,5"/>
         <Button x:Name="ButtonForward" Content="Forward（30s）" Width="220px" Margin="20,5"/>
         <Button x:Name="ButtonBack" Content="Back（30s）"Width="220px" Margin="20,5"/>
     </StackPanel>

ViewModel

    private MediaElement _mediaElementObject = new MediaElement();
    public MediaElement MediaElementObject
    {
        get { return _mediaElementObject; }
        set
        {
            _mediaElementObject = value;
            NotifyOfPropertyChange(() => MediaElementObject);
        }
    }

    public void ButtonPlay()
    {
        MediaElementObject.Source =new Uri( @"C:\Users\admin\Videos\XXXXXX.wmv");
        MediaElementObject.LoadedBehavior = MediaState.Manual;
        MediaElementObject.UnloadedBehavior = MediaState.Manual;
        MediaElementObject.Play();
    }     

    public void ButtonStop()
    {
        MediaElementObject.Stop();
    }
    public void ButtonForward()
    {
        MediaElementObject.Position = _mediaElementObject.Position + TimeSpan.FromSeconds(30);
    }
    public void ButtonBack()
    {
        MediaElementObject.Position = _mediaElementObject.Position - TimeSpan.FromSeconds(30);
    }

May can help someone:)

Answer 2

The answers above make use of MediaElement in the ViewModel. This element is a View-side component the VM should remain agnostic of.

One way to implement this would be exposing an event in your ViewModel via an interface that exposes that event, then have the view respond to that event by running its MediaElement, via code-behind, or perhaps using interactivity triggers.

ViewModel:

public interface ISoundPlayer
{
  event Action Play();
}    

public class MyViewModel : ViewModelBase, ISoundPlayer
{
  public event Action Play;
}

View:

public class MyView : UserControl
{
  ISoundPlayer _SoundPlayer;

  public MyView()
  {
    DataContextChanged += OnDataContextChanged;
    Unloaded += OnUnloaded;
  }  

  void OnDataContextChanged(DependencyObject sender, DataContextChangedEventArgs args)
  {
    if (DataContext is ISoundPlayer player && _SoundPlayer != player)
    {
      if (_SoundPlayer != null)
        _SoundPlayer.Play -= OnPlay;

      _SoundPlayer = player;
      _SoundPlayer.Play += OnPlay;
    }    
  }

  void OnUnloaded(object sender, RoutedEventArgs e)
  {
    if (_SoundPlayer != null)
      _Metronome.Play -= OnPlay;
  }

  void OnPlay() => myMediaElement.Play();
}

Answer 3

You can bind Media Element directly from the view model

in xaml:

<ContentControl Content="{Binding MediaElementObject}"/>

in ViewModel:

private MediaElement _mediaElementObject;

public MediaElement MediaElementObject
{
   get { return _mediaElementObject; }
   set { _mediaElementObject = value;RaisePropertyChanged(); }
}

And on OnNavigatedTo Override method you can create it's new object & can register it's events.

MediaElementObject=new MediaElement();

So that you can do all thing from the viewmodel itself.