I\'ve been trying to upload a file using the box v2 api with requests.
So far I had little luck though. Maybe someone here can help me see what I\'m actually doing wrong
My solution, using requests:
def upload_to_box(folder_id, auth_token, file_out):
headers = { 'Authorization' : BOX_AUTH.format(auth_token) }
url = 'https://api.box.com/2.0/files/content'
files = { 'filename': (new_file_name, open(file_out,'rb')) }
data = { 'folder_id': folder_id }
response = requests.post(url, params=data, files=files, headers=headers)
It would be nice if you could specify the new_copy
parameter but there's nothing documented for it and it doesn't seem to work.
You need to pass 2 Python dictionaries, files and data. files are {uniqFileName:openFileObj}
, and data are {uniqFileName:filename}
. Below is the upload method from my box class. And remember to add a final entry in data, 'folder_id': destination_id
.
def uploadFiles(self, ufiles, folid):
'''uploads 1 or more files in the ufiles list of tuples containing
(src fullpath, dest name). folid is the id of the folder to
upload to.'''
furl = URL2 + 'files/data'
data, files = {}, {}
for i, v in enumerate(ufiles):
ff = v[0]
fn = v[1]
#copy to new, renamed file in tmp folder if necessary
#can't find a way to do this with the api
if os.path.basename(ff) != fn:
dest = os.path.join(TMP, fn)
shutil.copy2(ff, dest)
ff = dest
f = open(ff, 'rb')
k = 'filename' + str(i)
data[k] = fn
files[k] = f
data['folder_id'] = folid
res = self.session.post(furl, files=files, data=data)
for k in files:
files[k].close()
return res.status_code
Here is a sample call:
destFol = '406600304'
ret = box.uploadFile((('c:/1temp/hc.zip', 'hz.zip'),), destFol)
Like I said, the above function is a method of a class, with an instance attr that holds a requests session. But you can use requests.post
instead of self.session.post
, and it will work just the same. Just remember to add the headers with your apikey and token if you do it outside a session.
According to the documentation, you are supposed to be able to rename the file by giving it a new name in the data dict. But I can't make this work except by copying the src file to a temp dir with the desired name and uploading that. It's a bit of a hack, but it works.
good luck, Mike
As someone requested my implementation, I figured I would put it out here for anyone trying to achieve something similar.
files_url = "%s/files/content" % (settings.BOX_API_HOST)
headers = {"Authorization": "BoxAuth api_key=%s&auth_token=%s" %
(settings.BOX_API_KEY, self.doctor.box_auth_token)
}
file_root, file_suffix = os.path.splitext(str(self.document))
filename = "%s%s" % (slugify(self.description), file_suffix)
files = {
'filename1': open(settings.MEDIA_ROOT + str(self.document), 'rb'),
}
data = {
'filename1': filename,
'folder_id': str(self.patient.get_box_folder()),
}
r = requests.post(files_url,
headers=headers,
files=files,
data=data)
file_response = simplejson.loads(r.text)
try:
if int(file_response['entries'][0]['id']) > 0:
box_file_id = int(file_response['entries'][0]['id'])
#Update the name of file
file_update_url = "%s/files/%s" % (settings.BOX_API_HOST, box_file_id)
data_update = {"name": filename}
file_update = requests.put(file_update_url,
data=simplejson.dumps(data_update),
headers=headers)
LocalDocument.objects.filter(id=self.id).update(box_file_id=box_file_id)
except:
pass
So in essence, I needed to send the file and retrieve the ID of the newly updated file and send another request to box. Personally, I don't like it either, but it works for me and haven't been able to find any other implementations that do the correct naming from the get-go.
Hope someone can benefit from this snippet.