When building a response in WCF (json), im pretty sure it\'s not possible to use completely dynamic objects, but just wanted to double check here first.
An ideal respons
Add the following using
at the top of your service implementation class (make sure that you also add the proper references in your project):
using Newtonsoft.Json;
using System.Dynamic;
using System.IO;
using System.Text;
You may try this simple method which outputs the dynamic result:
public string GetData()
{
dynamic d = new ExpandoObject();
dynamic bartSimpson = new ExpandoObject();
dynamic lisaSimpson = new ExpandoObject();
bartSimpson.url = "foo";
bartSimpson.desc = "bar";
lisaSimpson.url = "foo";
lisaSimpson.desc = "bar";
d.userTypes = new ExpandoObject();
d.userTypes.BartSimpson = bartSimpson;
d.userTypes.LisaSimpson = lisaSimpson;
var s = JsonSerializer.Create();
var sb = new StringBuilder();
using (var sw = new StringWriter(sb))
{
s.Serialize(sw, d);
}
return sb.ToString();
}
To go one more step further (you'll just have to pass Bart and Lisa in the comaSeparatedNames
value), you could do:
public string GetData(string comaSeparatedNames)
{
string[] names = comaSeparatedNames.Split(',');
dynamic d = new ExpandoObject();
dynamic dNames = new ExpandoObject();
foreach (var name in names)
{
dynamic properties = new ExpandoObject();
properties.url = "foo";
properties.desc = "bar";
((IDictionary<string, object>)dNames).Add(name, properties);
}
((IDictionary<string, object>)d).Add("userTypes", dNames);
var s = JsonSerializer.Create();
var sb = new StringBuilder();
using (var sw = new StringWriter(sb))
{
s.Serialize(sw, d);
}
// deserializing sample
//dynamic dummy = new ExpandoObject();
//var instance = s.Deserialize(new StringReader(sb.ToString()),
// dummy.GetType());
//var foo = instance.userTypes.BartSimpson.url;
return sb.ToString();
}
Note: I've also provided the lines (commented) for deserialization.